a) the distribution is "normal" because if population is normally distributed then sample is also normal distributed
b) standard error =σ/√n =5.9/√16 =5.9/4 =1.475
c)
μ=38
σ=5.9
x=39
z=(x-μ)/(σ/√n)
=(39-38)/(5.9/√16)
=1/1.475
=0.68
P(x>39) =P(z>0.68)
=1-P(z<0.68)
=1-0.7517
=0.2483
d)
μ=38
σ=5.9
x=36.5
z=(x-μ)/(σ/√n)
=(36.5-38)/(5.9/√16)
=-1.5/1.475
=-1.02
P(x>36.5) =P(z>-1.02)
=1-P(z<-1.02)
=1-P(x>39) =P(z>0.68)
=1-P(z<0.68)
=1-0.1539
=0.8461
e)
μ=38
σ=5.9
For x=36.5
z=(x-μ)/(σ/√n)
=(36.5-38)/(5.9/√16)
=-1.5/1.475
=-1.02
For x=39
z=(x-μ)/(σ/√n)
=(39-38)/(5.9/√16)
=1/1.475
=0.68
P(36.5<x<39) =P(-1.02<z<0.68)
=P(z<0.68)-P(z<-1.02)
=0.7517-0.1539
=0.5978
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