Answer
Given,
Randomly selected prices of 35 homes
309900 |
164900 |
227500 |
108500 |
220900 |
349500 |
355000 |
269900 |
150000 |
259500 |
139900 |
349900 |
159900 |
225000 |
247700 |
175000 |
235500 |
165000 |
275000 |
184900 |
185500 |
170000 |
162600 |
265500 |
175000 |
82500 |
249900 |
215000 |
265500 |
146000 |
174900 |
149900 |
159000 |
259900 |
224900 |
Mean=213128.57
Standard deviation=66306.36
N=35
1) Confidence interval
Formula for Confidence interval is given as
Mean ± Z*SD/sqrt(n)
Z value for 90% confidence interval is 1.645
213128.57±1.645*66306.36/sqrt(35)
213128.57±18436.86
CI=(194691.7,231565.4)
Margin of error=Z-value*SD
=1.645*66306.36
Margin of error =109074
2) we can state with 90% confidence that prices of homes will range between 194692 to 231565
For the next set of problems you can calculate Confidence interval and margin of error using the same formulae and below mentioned z values
level of confidence |
Critical value(Z) |
50% |
0.67 |
80% |
1.28 |
95% |
1.96 |
99% |
2.58 |
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325,000 225,000 118,000339,000 89,900 475,000 124,900 119,900 79,900138,000 154,900 149,900 39,900 229,500 374,900 129,900 95,900 169.,900 159,900 78,90084,900 149,900 149,900 524,900 269,900 159,900 105,900 349,000 54,900 309,000 144,900 395,000 239,000 159,900 304,900 Objective 2 (20 points) 1. Compute the following The average home price for your sample The standard deviation home price 2 Using complete sentences, define the random variable X 3. State the estimated distribution to use Use complete sentences and symbols where appropiate Objective 3 (20 points) Respond...
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