Question

I need help with this. Pictured first are a list of my questions, pictured second are my values I used.


Objective 1 (35 points) Using the website, www.zillow.com, randomly select 35 homes and record the price of each home. In the space below, clearly define how you randomly selected these homes and provide a table with the home costs you selected. Objective 2 (20 points) 1. Compute the following: The average home price for your sample S231,394.29 (231394.28571429 not rounded). The standard deviation home price 92776.312084678 or 92,776.31 (rounded) 2. Using complete sentences, define the random variable X. State the estimated distribution to use. Use complete sentences and symbols where appropriate. 3.
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media%2F026%2F026e3d4b-173d-4360-8d1b-8c
media%2Fee6%2Fee6dc859-f89d-487d-bc02-ec
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Answer #1

Answer

Given,

Randomly selected prices of 35 homes

309900

164900

227500

108500

220900

349500

355000

269900

150000

259500

139900

349900

159900

225000

247700

175000

235500

165000

275000

184900

185500

170000

162600

265500

175000

82500

249900

215000

265500

146000

174900

149900

159000

259900

224900

Mean=213128.57

Standard deviation=66306.36

N=35

1) Confidence interval

Formula for Confidence interval is given as

Mean ± Z*SD/sqrt(n)

Z value for 90% confidence interval is 1.645

213128.57±1.645*66306.36/sqrt(35)

213128.57±18436.86

CI=(194691.7,231565.4)

Margin of error=Z-value*SD

=1.645*66306.36

Margin of error =109074

2) we can state with 90% confidence that prices of homes will range between 194692 to 231565

For the next set of problems you can calculate Confidence interval and margin of error using the same formulae and below mentioned z values

level of confidence

Critical value(Z)

50%

0.67

80%

1.28

95%

1.96

99%

2.58

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