Question

In marketing, response modeling is a method for identifying customers most likely to respond to an...

In marketing, response modeling is a method for identifying customers most likely to respond to an advertisement. Suppose that in past campaigns 76.2% of customers identified as likely respondents responded to a nationwide direct marketing campaign. After making improvements to their model, a team of marketing analysts hoped that the proportion of customers identified as likely respondents who responded to a new campaign would increase. The analysts selected a random sample of 1500 customers and found that 1185 responded to the marketing campaign.

The marketing analysts want to use a one‑sample ?‑test to see if the proportion of customers who responded to the advertising campaign, ?, has increased since they updated their model. They decide to use a significance level of ?=0.01.

Select the correct null (?0) and alternative (?1) hypotheses.

?0:?=0.762 and ?1:?≠0.762

?0:?̂=0.762 and ?1:?̂>0.762

?0:?=0.762 and ?1:?>0.762

?0:?̂=0.790 and ?1:?̂>0.790

?0:?=0.790 and ?1:?>0.790

Determine the ?‑value for this test. Give your answer precise to at least three decimal places.

?=

Determine the value of the ?‑statistic. Give your answer precise to at least two decimal places.

?-value:

Select the correct decision and conclusion.

A. The analysts should reject the null hypothesis. There is insufficient evidence (?>0.01) that the proportion of customers who responded to the marketing campaign is greater than 0.762.

B. The analysts cannot make any valid decision or conclusion because the requirements for using a one-sample ?‑test for a proportion have not been met.

C. The analysts should not reject the null hypothesis. There is insufficient evidence (?>0.01) that the proportion of customers who responded to the marketing campaign is greater than 0.762.

D. The analysts should reject the null hypothesis. There is sufficient evidence (?<0.01) that the proportion of customers who responded to the marketing campaign is greater than 0.762.

E.The analysts should not reject the null hypothesis. There is sufficient evidence (?<0.01) that the proportion of customers who responded to the marketing campaign is greater than 0.762.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The null and alternative hypothesis is

?0:?=0.762 and ?1:?>0.762

Sample size = n = 1500

x = 1185

r 1185 n15000.79 n 1500

Test statistic is

z=\frac{\hat{p}-P_{0}}{\sqrt{P_{0}*(1-P_{0})/n}}

z=\frac{0.79-0.762}{\sqrt{0.762*(1-0.762)/1500}}=\frac{0.028}{\sqrt{0.000121}}=2.55

P-value = P(Z >2.55) = 0.0054

P-value < 0.01 we reject null hypothesis.

Conclusion: D. The analysts should reject the null hypothesis. There is sufficient evidence (?<0.01) that the proportion of customers who responded to the marketing campaign is greater than 0.762.

Add a comment
Know the answer?
Add Answer to:
In marketing, response modeling is a method for identifying customers most likely to respond to an...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In marketing, response modeling is a method for identifying customers most likely to respond to an...

    In marketing, response modeling is a method for identifying customers most likely to respond to an advertisement. Suppose that in past campaigns 68.4% of customers identified as likely respondents responded to a nationwide direct marketing campaign. After making improvements to their model, a team of marketing analysts hoped that the proportion of customers identified as likely respondents who responded to a new campaign would increase. The analysts selected a random sample of 1500 customers and found that 1059 responded to...

  • The absolute viscosity for sesame oil is supposed to average 0.0248 Pa⋅s at 50 ∘C. Suppose...

    The absolute viscosity for sesame oil is supposed to average 0.0248 Pa⋅s at 50 ∘C. Suppose a food scientist collects a random sample of 3 quantities of sesame oil and computes the mean viscosity for his sample to be ?⎯⎯⎯=0.0252 Pa⋅sx¯=0.0252 Pa⋅s at 50 ∘C Assume that measurement errors are normally distributed and that the population standard deviation of sesame oil viscosity is known to be ?=0.0003 Pa⋅s The scientist will use a one‑sample ?z‑test for a mean, at a...

  • Would you favor spending more federal tax money on the arts? Of a random sample of...

    Would you favor spending more federal tax money on the arts? Of a random sample of n = 93 politically conservative voters, 1 = 17 responded yes. Another random sample of n2 = 78 politically moderate voters showed that r2 - 22 responded yes. Does this information indicate that the population proportion of conservative voters inclined to spend more federal tax money on funding the arts is less than the proportion of moderate voters so inclined? Use a = 0.05....

  • Before the furniture store began its ad campaign, it averaged 147 customers per day. The manager...

    Before the furniture store began its ad campaign, it averaged 147 customers per day. The manager is investigating if the average has changed since the ad came out. The data for the 12 randomly selected days since the ad campaign began is shown below: 147, 128, 147, 149, 127, 137, 157, 139, 146, 151, 133, 124 Assuming that the distribution is normal, what can be concluded at the α = 0.01 level of significance? a. For this study, we should...

  • 19% of all college students volunteer their time. Is the percentage of college students who are...

    19% of all college students volunteer their time. Is the percentage of college students who are volunteers larger for students receiving financial aid? Of the 308 randomly selected students who receive financial aid, 65 of them volunteered their time. What can be concluded at the α = 0.01 level of significance? a. For this study, we should use: Z-test for a population proportion or t-test for a population mean? b. The null and alternative hypotheses would be: H 0 :...

  • 1) A psychologist claims that more than 62 percent of the population suffers from professional problems...

    1) A psychologist claims that more than 62 percent of the population suffers from professional problems due to extreme shyness. Assuming that a hypothesis test of the claim has been conducted and that the conclusion is failure to reject the null hypothesis, state the conclusion in nontechnical terms. There is sufficient evidence to support the claim that the true proportion is less than 62 percent. There is sufficient evidence to support the claim that the true proportion is greater than...

  • Based on information from a previous study, r = 34 people out of a random sample...

    Based on information from a previous study, r = 34 people out of a random sample of n = 101 adult Americans who did not attend college believe in extraterrestrials. However, out of a random sample of n2 = 101 adult Americans who did attend college, '2 = 47 claim that they believe in extraterrestrials. Does this indicate that the proportion of people who attended college and who believe in extraterrestrials is higher than the proportion who did not attend...

  • In a previous poll, 36% of adults with children under the age of 18 reported that...

    In a previous poll, 36% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 378 of 1108 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased?...

  • Customers who participate in a store's free loyalty card program save money on their purchases, but...

    Customers who participate in a store's free loyalty card program save money on their purchases, but allow the store to keep track of the customer's shopping habits and potentially sell these data to third parties. A Survey revealed that 225 of a random sample of 250 U.S. adults would agree to participate in a store loyalty card program, despite the potential for information sharing. Let p represent the true proportion of all customers who would participate in a store loyalty...

  • a sample of 113 observations indicated that X1 is 71. A second sample of 157 observations indicated...

    a sample of 113 observations indicated that X1 is 71. A second sample of 157 observations indicated that X2 is 95. Conduct a z-test of hypothesis about a difference in population proportions using a 0.03 significance level.     H0: p1 - p2 ≥ 0     H1: p1 - p2 < 0 a)State the decision rule.Reject H0 in favour of H1 if the computed value of the statistic is less than -1.88 or greater than 1.88.Reject H0 in favour of H1 if the computed value of the statistic is greater than 2.17.Reject H0 in favour of H1 if the computed...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT