Question

QUESTION 1 A car of mass 500 kg is accelerated from an initial velocity of 10 m/s. Its final velocity when the total work done by the car 1400 J in m/s is O 15.4 12.1 20.2 10.3

Answer 1

Solution::

$V_{1}=10m/s$. =Initial velocity of car

m= 500 kg = mass of car

Let's the final velocity of car is $V_{2}$

W = work done by car =1400 J

We know that then work done by car  $\frac{1}{2}mV^{2}_{2} -\frac{1}{2}mV^{2}_{1}$

So that is clear both work done by car so both are same

$\frac{1}{2}mV^{2}_{2} -\frac{1}{2}mV^{2}_{1} = 1400$

mV,1- mV,1 = 1400 * 2

$V^{2}_{2} -V^{2}_{1} = 1400*2*\frac{1}{m}$

$V^{2}_{2} -(10m/s)^{2} = (1400J)*2*\frac{1}{500kg}$

$V^{2}_{2} -100m^{2}/s^{2}=\frac{28}{5}m^{2}/s^{2}$

The final velocity of car is 10.3 m/s

ANSWER = 10.3 m/s