Al4C3 + 12 H2O = 4Al(OH)3 + 3CH4
Moles of Al4C3 = mass / molar mass
= 232 / 144
= 1.611
Moles of water = 12*moles of Al4C3 ( look balance equation
= 12* 1.611
= 19.33 moles
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Consider the following unbalanced equation: How many moles of water are needed to react with 232....
Consider the following unbalanced equation: Al4C3 + H2O Al(OH)3 + CH4 How many moles of water are needed to react with 215. g of Al4C3?
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