Question

Claim: ACT Scores will increase when a student takes the ACT a second time, even without additional preparation. You are investigating the validity of this claim. Use a confidence level of 0.05. Let V1 = Initial ACT score, 2 = Second ACT score.


 DATA: A total of 25 students participated in the study. Each student has two ACT scores. The scores for each student are listed in the Excel file that you should have downloaded at the beginning of the exam. 


You are investigating the validity of this claim. Clearly label each portion of your answer as STEP 1 through STEP 6.


D F m B Initial ACT Second ACT WN 1 2 18 30 22 29 8 4 5 6 7 8 9 10 11 12 13 14 15 А Individual 1 2 3 4 5 6 7 8 9 10 11 12 13



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Answer #1

Given that,
mean(x)=24.72
standard deviation , s.d1=3.831
number(n1)=25
y(mean)=23.64
standard deviation, s.d2 =3.938
number(n2)=25
null, Ho: u1 = u2
alternate, H1: u1 > u2
level of significance, α = 0.05
from standard normal table,right tailed t α/2 =1.711
since our test is right-tailed
reject Ho, if to > 1.711
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =24.72-23.64/sqrt((14.67656/25)+(15.50784/25))
to =0.9829
| to | =0.9829
critical value
the value of |t α| with min (n1-1, n2-1) i.e 24 d.f is 1.711
we got |to| = 0.98288 & | t α | = 1.711
make decision
hence value of |to | < | t α | and here we do not reject Ho
p-value:right tail - Ha : ( p > 0.9829 ) = 0.16773
hence value of p0.05 < 0.16773,here we do not reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 > u2
test statistic: 0.9829
critical value: 1.711
decision: do not reject Ho
p-value: 0.16773
we do not have enough evidence to support the claim that ACT scores will increase when a student takes the ACT a second time even without additional preparation.

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