Question 1: (20 points) Find the solution of the initial value problem a = cos? x...
Find the solution y of the initial value problem 3"(t) = 2 (3(t). y(1) = 0, y' (1) = 1. +3 g(t) = M Solve the initial value problem g(t) g” (t) + 50g (+)? = 0, y(0) = 1, y'(0) = 7. g(t) = Σ Use the reduction order method to find a second solution ya to the differential equation ty" + 12ty' +28 y = 0. knowing that the function yı(t) = + 4 is solution to that...
show all working 2. Find the solution to the following differential equation with initial value (20 points) y" + 2y + 5y = 4e * cos(2x) with y(0) = 0 and y(0) = 1
3. (20 points) Find the solution y = y(x) of the initial value problem y 0 − y x = cos2 (y/x) , y(1) = π 3 3. (20 points) Find the solution y = y(x) of the initial value problem 37 - = cos”(y/2),y(1) = 5
6. Solve the initial value problem y" + y = 0, y(0)=0, y'0=1 (a) -COS X (b) -sin x (c) -sin x + cos x (d) -sin x COS X (e) COS X (f) sin x (g) sin x-COS X (h) sin x + cos x 7. Find a particular solution yn of the differential equation (using the method of undetermined coefficients): y + y =p2 (a) 2e (b) 3e (c) 4e: (d) 6e (e) 2/2 (f) e2/3 (g) e2/4...
Exact Differential Equations. Let y(x) be the solution of the following initial value problem: (cos z ln(2y = 8) + 2) + (x+4)=0, x(1) -- What is the value of y(+/2)? (a) 37 + 1. (b) 1/7- 2. (c) /3+ V. (d) 4+1/. (e) None.
1. (5 points) Find an interval containing x 0for which the given initial value problem has a unique solution. y=x2 +2 +cos(x 1. (5 points) Find an interval containing x 0for which the given initial value problem has a unique solution. y=x2 +2 +cos(x
QUESTION 19 Find the solution to the initial value problem dy 6xy + y2 + (3x2 + 2xy + 2y) dc = 0 { wives y(1) = 3 ОА. 3x²y + xy² + y2 = 27 xºy + x²y2 + y2 + x = 22 Ос. 3.xạy + 2x^y + x3 + 2x2 + 2y = 24 x+y + 2xy2 + y2 + x = 31 OL 6xy + 2y2 + x = 37
Chapter 3, Section 3.5, Question 15 Find the solution of the initial value problem y" + 2y' + 5У-16e-t cos (2t), y (0)-4, y, (0-0. Enclose arguments of functions in parentheses. For example, sin (2x) Equation Editor Ω Common Matrix 亩。 sin(a) ca) tanta) sec(a) ese(a cot(a sin (a) y (t) Click if you would like to Show Work for this question: Open Show Work Chapter 3, Section 3.5, Question 15 Find the solution of the initial value problem y"...
solution for all 4 please In Problems 1-3, solve the given DE or IVP (Initial-Value Problem). [First, you need to determine what type of DE it is. 1. (2xy + cos y) dx + (x2 – x sin y – 2y) dy = 0. 1 dy 2. + cos2 - 2.cy y(y + sin x), y(0) = 1. + y2 dc 3. [2xy cos (2²y) – sin x) dx + x2 cos (x²y) dy = 0. (1+y! x" y® is...
Find the solution of the given initial value problem. y" + 2y' +2y = cost+8(-5); y(0) = 3, y'(0) = 5 ° 20) = us20e" sin + + cost ( +ş) + sint (36+}) x() ==««n6e8cose + cost (3e* +) + sint (80* + }) 20 = usz beé" sin + sing (54* +5.) +cos (34++}) ° 40 = =uaz(Dei* cost + cost ("* + 5 ) + sint (3*+ }) 209 = 192(e“ cose + cost (* +) +sint(****+})