Question

30 Consider the reaction of solid PbO and gaseous NH3 to form solid Pb, nitrogen gas, and water vapor. Write the balanced chemical equation for the reaction. a O of 0.25 points earned 3 attempts remaining how many moles of NH3 are required to produce 185.6 grams of Pb ? O of 0.25 points earned 3 attempts remaining how many grams of N2 will be produced from 0.447 moles of Pbo? C O of 0.25 points earned 3 attempts remaining d how many grams of NH3 will be required to react with 32.7 grams of PbO ? O of 0.25 points earned 3 attempts remaining

Answer 1

(9) 3PbOg) + 2NH3(g) -> 3Pb(s) + N2(g) + 34,068) 6) Keeping above balanced chemical deaction in mind, we'll calculate further Moles of Pb = Massot Pb given Mdecular mass of Pb - 185.6 207-2 = 0-895 moles Moles of NH3 required - 0.895x2 = 0,596 moles C) Moles of Nel produced = 0.447 3 = 0.14 9 moles Mass (grams) of Ng required = o.149 x molecular mass of Na = 0.149x 28 = 4-172 gram ( Calculated by keeping the above balanced chemical reaction in mind (d) keeping the above balanced chemical reaction lab in mind Moles of PbO - Mass of Pbo guren Molecular mass og PbO c 32-7 22-3-1 = 0-146 moles Mass of NH3 required = o. 146 x 2 x15 (grams) = 1.46 grams 2