Question

Previous Problem Problem List Next Problem (4 points) in 1987. X-ray diffraction was used to determine that the thermal expansion of the protein metmyoglobin led to the increase of protein diameter by 4% after an increase in temperature from 80 Kto 320 K What is the estimated VOLUME expansion coefficient for this protein BE

Answer 1

The expression for the volume of the spherical protein is represented as follows: Here, r is the radius. The radius is represented as follows: D 1=- 2 Here, D is the diameter. Therefore, Differentiate it with respect to d. albe (D)** (313) dv = SAD’dD The expression for the volume expansion is represented as follows: dV = BVDT B- dv VdT Here, B is the coefficient of volume expansion, dV is the increase in volume, V is the volume, and dT is the temperature.

Therefore, GAD’DD 1-C)* |(320 K –80 K) 320 K -80 K) 3dD D(320 K -80 K) According to the question, the increase in diameter is represented as follows: dD = 4%D dD D=0.04 Substitute 0.04 for B7320 3(0.04) (320 K -80 K) = 0.0005 K- = 5x10-4K-1 Therefore, the coefficient of volume expansion is 5x10* K'.