Question

Problem 1. For the beam below, use either the "tabulated values" method or the influence-line equations" method to: (a) Draw the influence lines for reactions A, and MA. (b) Draw the influence lines for the reaction at C. (c) Draw the influence lines for the moment at C. (d) Determine the maximum positive and negative values of the reactions at A and C if the span can be loaded with a 1.2kips/ft uniform load of variable length and a Skips moving load. (e) Determine the maximum positive and negative values of the moment at A if the span can be loaded with a 1.2kips/ft uniform load of variable length and a Skips moving load. (t) Determine the maximum positive and negative values of the moment at C if the span can be loaded with a 1.2kips/ft uniform load of variable length and a 5kips moving load. Show ALL free-body diagrams and ALL your calculations. MA, RA, MC, VC

Answer 1

Unit spot at ^ , ERO unit lood at A FRO Me Me 148 TBA +1] [Mq=Me=bl. Rezo unit lovl Rast at B - Mczo MA= -1X123 -12 Mas -|X12 = -2, Rool Rezo amit load etc MA to 12 to to Bal 7 Me t a MADRAD, 1=1, Moro unit loud ato s Mc. in % 12' 4 1/2 J RAZL 6 121 2 2 Rc Bending at B=0 Mcc-176 Me=-6 RA=-1/2 MA= {X12 = 6 -1* 18+ Rex19 -0, Re: 32

Ils for RA 0 for the RA 1+1/7.1001 RA (max) = 5x + 4x12X 1-2 X1 + 12X12 = 21.6k por Maximum (-vo boodsk Rap-wr mox) = {(**) *1-2x6 =5x) - 4.3k I lotor Re Kc (ve) moxmem 1216 K: (+mex - x x 13x1.2 + 5x3 237k RE (-)man -0. Il fes MA 1-2 kift ISK Mitve) mar a Max = SX 6+ KX 6X6X1-2 = 51.6 kft Minox SKS - 216/ -2 MH Mimon = 5X1-12) – 4 x 12 x 1-2 x 24 = 232.2 Kit Elsker Me Me 2 P MI imor] =0, 1-2K/A 15 Mc moal = -6X5-X6X 1-2 X6 = -51.6 kft.