Question

Question 1 (1 point) What is the deltaG for transporting 2 moles of Cl- from the inside of a parietal cell to the stomach cavity, when the (Cl-) inside the cell = 250 uM and Cl-) in the stomach cavity = 0.15mM? Assume membrane potential is -60mV (inside negative). 0-14.21 kJ 14.21 kJ 0-7.11 kJ O-7.11 kJ/mol

Answer 1

Given, R = 8.314 J K t molt F=96500 J mest aut c = 250 MM = 0.250 mm C₂ = 0.15 mm T= 310k OV=-60 mV = -60x10 3 v We know on calculation with electrical potential is given by for a OG = RT en q + 2 FOV Z=1 0.15 mm H + 1x 96500 Inott ut OG = 8.314 J K mot x310 R en 0.25mm x 6-60x103) oh = - 1316.57 I molt – 5790 I molt oh=-7106.57 J molt -it. 107 kJ/mol For Imoles of the transporting from inside to outside OG = nog = 2 x (-7. 10.7 kJ / mod) =-14.214 KJ lative Hence, answer is (A) - 14.21 KJ (Note: - Then sign represent the flow of a from higher oncentration to lower concentration which is favourable process.)