As the two charges are of same sign, so, the electric field is
zero in between the charges. So, we assume that the zero electric
field point to be at a distance x from the origin. And if we assume
that the distance between the two charges is d, then, we get
where, is situated at the
origin. And is situated at the
distance d.
So, for E(x) = 0, we require
Now for the given values,
and so,
For the +ve sign, we have
And for d = 0.58 m, we have
And for -ve sign , we have
And for d = 0.58 m, we have
And as this is greater than 0.58 m, so, this can't be the answer.
So, the correct answer is
Please also include formulas used 2. Two positive charges are located a distance of 0.58 m...
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Two point charges are placed on the x axis. (Figure 1) The first charge, q1 = 8.00 nC , is placed a distance 16.0 m from the origin along the positive x axis; the second charge, q2 = 6.00 nC , is placed a distance 9.00 m from the origin along the negative x axis. Part A Calculate the electric field at point A, located at coordinates (0 m, 12.0 m ).
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