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Consider the data set that is summarized in below. -------------------------------------------------------------------------------------------------- Source DF Adj SS Adj MS...

Consider the data set that is summarized in below.

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Source DF Adj SS Adj MS F-Value P-Value
C2 2 78.73 39.36 2.80 0.075
Error 34 477.90 14.06
Total 36 556.62

S = 3.749 R-Sq = 14.14% R-Sq(adj) = 9.09%
Level N Mean StDev
1 10 7.699 3.808
2 10 11.656 3.859
3 17 9.461 3.651


Pooled StDev = 3.749


Fisher Individual Tests for Differences in Means
Difference
of Levels		 Difference
of Means		 93% CI T-Value Adjusted
P-Value
2 - 1 3.957 (0.820, 7.094) ? ?
3 - 1 1.762 (-1.033, 4.558) ? ?
3 - 2 -2.195 (-4.990, 0.601) ? ?

Simultaneous confidence level = 83.72%
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(a) Find a 93% Fisher confidence interval for μ3 − μ1.
(b) Which pairs of means are significantly different (using Fisher's LSD method at the 7% significance level)?
math   Statistics-And-Probability   
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Answer #1

(a) Step1 The value of the pooled standard deviation is (17-1)13.3298+(10-114.50086 17+10-2 (16)13.3298+(9 (14.50086) 27-2 213.2768+130.5078 25 343.7846 25 13.75138 = 3.708286 , 3.708286 Step3 The value of s1S 72 37082861 -3.7082860.058824 +0.1 = 3.708286 0.1 58824 3.708286 0.398527) 1.477851 s = 1.477851 Step3 The 93% confidence interval for the difference between population means 1S A3- A1 = (9.461-7.699) ±1.892928(1.477851) = 1.762 ± 2.797466 -1. 03547 4.559466 쟈-X1) ±40129 103547 SA-AS 4.5594 Step4 Interpretati on we can be 93% confident that the difference between the population means is between -1.03547 and 4.5594

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