Answer:
Problem #4: Consider the data set that is summarized in the Minitab Output below Source DF C2 Err...
- Consider the data set that is summarized in the Minitab Output below. Source DF C2 Error 34 Total 36 Adj SS 122.79 210.34 333.13 Adj MS 61.39 6.19 E-Value 9.92 P-value 0.000 S = 2.487 R-Sq = 36.86% R-Sq(adj) = 33.15% Level N Mean 1 10 12.517 2 9 7.673 18 9.100 St Dev 3.261 0.928 2.518 Pooled St Dev = 2.487 Fisher Individual Tests for Differences of Means Difference of Levels Adjusted p-Value T-Value 2 Difference of Means...
Consider the data set that is summarized in the Minitab Output below. -------------------------------------------------------------------------------------------------- Source DF Adj SS Adj MS F-Value P-Value C2 2 67.46 33.73 7.36 0.002 Error 34 155.71 4.58 Total 36 223.17 S = 2.140 R-Sq = 30.23% R-Sq(adj) = 26.12% Level N Mean StDev 1 12 8.386 2.071 2 12 10.638 2.269 3 13 11.608 2.080 Pooled StDev = 2.140 Fisher Individual Tests for Differences of Means Difference of Levels Difference of Means 97.6667% CI T-Value Adjusted...
Consider the data set that is summarized in the Minitab Output below. (a) Find a 93% Bonferonni confidence interval for μ2 − μ1. (b) Which pairs of means are significantly different (using the Bonferonni method at the 7% significance level)? Problem #4(a): (A) 2 and 3 only (B) 1 and 3 only (C) 1 and 2, 2 and 3 only (D) all of them (E) none of them (F) 1 and 3, 2 and 3 only (G) 1 and 2,...
Consider the data set that is summarized in below. -------------------------------------------------------------------------------------------------- Source DF Adj SS Adj MS F-Value P-Value C2 2 78.73 39.36 2.80 0.075 Error 34 477.90 14.06 Total 36 556.62 S = 3.749 R-Sq = 14.14% R-Sq(adj) = 9.09% Level N Mean StDev 1 10 7.699 3.808 2 10 11.656 3.859 3 17 9.461 3.651 Pooled StDev = 3.749 Fisher Individual Tests for Differences in Means Difference of Levels Difference of Means 93% CI T-Value Adjusted P-Value 2 -...
Consider the data set that is summarized in the MInitab output below. SAMPLE N Mean StDev 95% CI 1 36 109.81 12.12 (?, ?) 2 13 126.57 9.71 (?, ?) 3 14 ? 11.09 (?, ?) Suppose that the following is a Bonferonni confidence interval for μ1 − μ3, (2.04, 8.91). If we were to use ANOVA to analyze the above data, what would be the value of SS(treatment)?
1. Consider the following data set and the Minitab output. Derive (ie., calculate) each number that has a superscript next to it in the upper right-hand comer.. Show all of your work in complete detail. Data Display x Y Row 1 3 14 5 16 7 20 4 2 3 5 13 8 19 23 24 5 6 9 7 10 14 22 9 20 38 10 22 39 Descriptive Statistics: X, Y Variable N NMean SE Mean StDev Minimum...
Consider the data that is summarized in the Minitab output below. Descriptive Statistics: C1, C2 Variable N Mean SE Mean StDev Minimum Q1 C1 25 161.56 6.72 33.58 106.00 125.00 C2 17 185.59 6.32 26.05 181.00 197.50 Median Q3 Maximum 143.00 167.50 234.00 208.00 227.50 288.00 Suppose that we want to test the hypothesis that the mean for population 1 is less than the mean for population 2, assuming the the population variances are equal. The test statistic is found...
PLEASE SOLVE USING ALL MANUAL CALCULATIONS, Z-SCORE TABLES, T-SCORE TABLES, ETC. Problem #2: Using the data from Problem #1 above, we want to use the Bonferonni method to test the following hyptheses at the 3% significance level (a) Find the value of the test statistic for each of the above three hypotheses (in the above order) (b) which pairs of means are significantly different (using the Bonferonni method at the 3% significance level)? 3 test statistics (correct to 2 decimals)...
Problem #6: Consider the data set that is summarized in the Minitab Output below Stem-and-Leaf Display: C1 Stem-and-leaf of Ci N = 13 Leaf Unit = 1.0 1 1 5 2 2 7 2 3 4 4 17 |(6) 5 339999 3 6 357 (a) Find the values of Q1 and Q3. (b) Find the median (c) Find the adjacent values (Note: Read the last two pages of this file for the relevant definitions, and for an example.) (d) Which...