Question

Consider the data that is summarized in the Minitab output below.   Descriptive Statistics: C1, C2 Variable...

Consider the data that is summarized in the Minitab output below.  
Descriptive Statistics: C1, C2
Variable N Mean SE Mean StDev Minimum Q1
C1 25 161.56 6.72 33.58 106.00 125.00
C2 17 185.59 6.32 26.05 181.00 197.50
Median Q3 Maximum
143.00 167.50 234.00
208.00 227.50 288.00

Suppose that we want to test the hypothesis that the mean for population 1 is less than the mean for population 2, assuming the the population variances are equal. The test statistic is found to be −2.48 . Find the p-value. Assume that the populations are normal.

(A) .025 < p-value < .05   (B) .005 < p-value < .01   (C) .01 < p-value < .025   (D) .0066   (E) .0132  

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Answer #1

The null and alternate hypothesis are:

H0:

Ha:

Thus, it is a left-tailed test.

Since this a left tailed test, so the p-value is given by:

Hence option D is the correct option.

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