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Consider the data set that is summarized in the Minitab Output below. --------------------------...
Problem #4: Consider the data set that is summarized in the Minitab Output below Source DF C2 Error 34 Total 36 Adj SS 86.12 104.98 191.10 Adj MS 43.06 3.09 F-Value 13.95 P-Value 0.000 S 1.157 R-Sq Level NMean 2 45.06% R-Sq ( adj) -41.83% StDev 9 8.4151.458 10 11.4012.106 18 7.807 1.681 Pooled StDev- 1.757 Fisher Individual Tests for Differences of Means Difference Difference of Levels Adjusted P-Value of Means 97。6667% CI T-Value (1.068, 4.903) 0.608(-2.312, 1.095) -3.594 (-5.239,...
Consider the data set that is summarized in the Minitab Output below. (a) Find a 93% Bonferonni confidence interval for μ2 − μ1. (b) Which pairs of means are significantly different (using the Bonferonni method at the 7% significance level)? Problem #4(a): (A) 2 and 3 only (B) 1 and 3 only (C) 1 and 2, 2 and 3 only (D) all of them (E) none of them (F) 1 and 3, 2 and 3 only (G) 1 and 2,...
- Consider the data set that is summarized in the Minitab Output below. Source DF C2 Error 34 Total 36 Adj SS 122.79 210.34 333.13 Adj MS 61.39 6.19 E-Value 9.92 P-value 0.000 S = 2.487 R-Sq = 36.86% R-Sq(adj) = 33.15% Level N Mean 1 10 12.517 2 9 7.673 18 9.100 St Dev 3.261 0.928 2.518 Pooled St Dev = 2.487 Fisher Individual Tests for Differences of Means Difference of Levels Adjusted p-Value T-Value 2 Difference of Means...
Consider the data set that is summarized in below. -------------------------------------------------------------------------------------------------- Source DF Adj SS Adj MS F-Value P-Value C2 2 78.73 39.36 2.80 0.075 Error 34 477.90 14.06 Total 36 556.62 S = 3.749 R-Sq = 14.14% R-Sq(adj) = 9.09% Level N Mean StDev 1 10 7.699 3.808 2 10 11.656 3.859 3 17 9.461 3.651 Pooled StDev = 3.749 Fisher Individual Tests for Differences in Means Difference of Levels Difference of Means 93% CI T-Value Adjusted P-Value 2 -...
Consider the data set that is summarized in the MInitab output below. SAMPLE N Mean StDev 95% CI 1 36 109.81 12.12 (?, ?) 2 13 126.57 9.71 (?, ?) 3 14 ? 11.09 (?, ?) Suppose that the following is a Bonferonni confidence interval for μ1 − μ3, (2.04, 8.91). If we were to use ANOVA to analyze the above data, what would be the value of SS(treatment)?
1. Consider the following data set and the Minitab output. Derive (ie., calculate) each number that has a superscript next to it in the upper right-hand comer.. Show all of your work in complete detail. Data Display x Y Row 1 3 14 5 16 7 20 4 2 3 5 13 8 19 23 24 5 6 9 7 10 14 22 9 20 38 10 22 39 Descriptive Statistics: X, Y Variable N NMean SE Mean StDev Minimum...
Consider the data that is summarized in the Minitab output below. Descriptive Statistics: C1, C2 Variable N Mean SE Mean StDev Minimum Q1 C1 25 161.56 6.72 33.58 106.00 125.00 C2 17 185.59 6.32 26.05 181.00 197.50 Median Q3 Maximum 143.00 167.50 234.00 208.00 227.50 288.00 Suppose that we want to test the hypothesis that the mean for population 1 is less than the mean for population 2, assuming the the population variances are equal. The test statistic is found...
Method Null hypothesis H₀: All means are equal Alternative hypothesis H₁: At least one mean is different Equal variances were assumed for the analysis. Factor Information Factor Levels Values StressLevel 3 High, Low, Medium Analysis of Variance Source DF Adj SS Adj MS F-Value P-Value StressLevel 2 261.361 130.681 18.76 <0.0001 Error 69 480.583 6.965 Total 71 741.944 Model Summary S R-sq R-sq(adj) R-sq(pred) 2.63912 35.23% 33.35% 29.47% Means StressLevel N Mean StDev 95% CI High 24 5.2083 2.6536 (4.1336,...
The operations department has a business objective of reducing the amount of time to fully update each subscriber's set of messages in a secured email system. An experiment was conducted where 24 subscribers were selected and 3 different messaging systems were used. 8 subscribers were assigned to each system and the update times were measured. Sys 1 Sys 2 Sys 3 38.8 41.8 32.9 42.1 36.4 36.1 45.2 39.1 39.2 34.8 28.7 29.3 48.3 36.4 41.9 37.8 36.1 31.7 41.1 ...
Problem #6: Consider the data set that is summarized in the Minitab Output below Stem-and-Leaf Display: C1 Stem-and-leaf of Ci N = 13 Leaf Unit = 1.0 1 1 5 2 2 7 2 3 4 4 17 |(6) 5 339999 3 6 357 (a) Find the values of Q1 and Q3. (b) Find the median (c) Find the adjacent values (Note: Read the last two pages of this file for the relevant definitions, and for an example.) (d) Which...