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Calculate the pH at 25 °C of a 0.26 M solution of lidocaine HCI (C14H2, NONH, CI). Note that lidocaine (C14H 2, NONH) is a we

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Answer #1

pKb for C4H2, NONH = 7.94 pka for C14H22NONH,= 14 – pKb = 14 – 7.94 = 6.06 Ka = 8.71 x 10-7 M Cahy, NONA, “ C14H21 NONH NH +

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