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Calculate the pH at 25 °C of a 0.96 M solution of ethylammonium bromide (C2HNH2Br). Note that ethylamine (C2H3NH2) is a weak

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Answer #1

Answer : pH = 12.39

explanation:

kriting the equilibria, C2 Hs NH₃ + H₂O SHs Ntg + OHO We have pkb = 3.19, they we can calculate Kb, Кь - -- PRь = 10 -3.19 Kbplease upvote

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