base = 120 x 0.7513 = 90.156
volume of salt at equivalence point = 90.156 /
0.4926 = 183. 0 m
salt concentration = 90.156 / 183 +120 = 0.2975 M
pH = 7 - 1/ 2[pKb + log C]
= 7 - 1/2 [7.94 + log 0.2975 ]
= 3.29
pH = 3.29
Calculating the pH at equivalence of a titration A chemist titrates 120.0 mL of a 0.7513...
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