Question

ACIDS AND BASES Calculating the pH at equivalence of a titration A chemist titrates 200.0 mL of a 0.5694 M sodium hydroxide (NaOH) solution with 0.6230 M HCl solution at 25 °C. Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added. PH-0 5 ?

Answer 1

Mini Anis from question Given Volume of Nacoes (V)= 200 ml = OILL Malinity of NooH &M, D= 0.5694m moles of Nach 0.5694 M XO-22 = 0.11388 moles Malarity of HU (MJ = 0.6230m HU LV₂ ) = ? at equivalence point number of moles of HU = number of males of Neot M₂ V2 Mv, volume of 0.6230M XV₂ = 0.5694M X 0.2L V₂ = 0.5694 M XO:2L 0.623om 0. 1828 L 182.8 ml Nach + How NaOH + HU 0.1138 moles 0.1138 males In this case all the acid react with all the base neubalization takes place pH = 7.00 CScanned with CamScanner