Question

Determine the average value of the translational kinetic energy of the molecules of an ideal gas at (a) 29.4^degreeC and (b) 100^degreeC. What is the translational kinetic energy per mole of an ideal gas at (c) 29.4^degreeC and (d) 100^degreeC?

Answer 1

Using the following relations:

The average translational kinetic energy of any kind of molecule in an ideal gas is given by k - Boltzmann constant R/NA kー1·38066x10-23ΛΚ avg-2kr molecule per R-universal gas constant kN mole avg R= 8.3145 J/mol K

Changing temperatures to Kelvin

29.4^oC=302.55K

100^oC=373.15K

a) Subtituting values we get:

6.27*10^-21 J

b) Subtituting values we get:

7.73*10^-21 J

c) Subtituting values we get:

3775.85 J

d) Subtituting values we get:

4655.08 J