n =
247 = 13 * 19
so,
p = 13 & q = 19
( n ) = (13-1) *
(19 -1) = 216
e =25
secret key is d such that
e*d = 1 mod 216
using eucledian theorem
d is multiplicative inverse of e in Z216
q | r1 | r2 | r | t1 | t2 | t |
---|---|---|---|---|---|---|
8 | 216 | 25 | 16 | 0 | 1 | -8 |
1 | 25 | 16 | 9 | 1 | -8 | 9 |
1 | 16 | 9 | 7 | -8 | 9 | -17 |
1 | 9 | 7 | 2 | 9 | -17 | 26 |
3 | 7 | 2 | 1 | -17 | 26 | -95 |
2 | 2 | 1 | 0 | 26 | -95 | 216 |
1 | 0 | -95 | 216 |
t = t1 -q*t2
t1 = t2
t2 = t
value of t = -95 or (216 - 95) = 121
so d =121
where secret key = (d,n) = (121 , 247)
signature = md mod n
= 63121 mod 247 = 232
Exercise 1 (2 pts). Alice has her RSA public key (n,e) where n = 247 =...
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