Question

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Q) Consider compressed video transmission in an ATM network. Suppose standard ATM cells must be transmitted through 5 switches. The data rate is 43 Mbps.  
a. What is the transmission time for one cell through the switch?
b. Each switch may be transmitting a cell from other traffic all of which we assume to      have lower (non-preemptive for the cell) priority. If the switch is busy transmitting     a cell, our cell has to wait until the other cell completes transmission. If the switch      is free our cell is transmitted immediately. What is the maximum time from when a      typical video cell arrives at the first switch (and possibly waits) until it is finished     being transmitted by the fifth and last one? Assume that you can ignore     propagation time, switch time, and everything else but the transmission time and      the time spent waiting for another cell to clear a switch.
c. Now suppose we know that each switch is utilized 60% of the time with the other      low-priority traffic. By this we mean that with probability 0.6 when we look at a     switch it is busy. Suppose that if there is a cell being transmitted by a switch, the      average delay spent waiting for a cell to finish transmission is one-half a cell’s      transmission time. What is the average time from the input of the first switch to     clearing the fifth?
d. However, the measure of the most interest is not delay but jitter, which is the     variability in the delay. Use parts (b) and (c) to calculate the maximum and      average variability, respectively, in the delay.