Question

of water In another experiment, a student dissolved 78.35 g FeCl3-6 H2O in 75.80 g water and reported the density of the solution to be 1.098 g/mL. SHOW WORK to calculate for this solution the per cent salt. (Note this solute is part salt and part water of hydration.) molarity molality

# 2 only not 4

Answer 1

Ans. weight of solute ( KClO₃) = 3.53g volume of solution at 45° C = 45 ml. a percent sat weight tos volume ta Yo wlu = t. of solute volume of solution x100 - 2015 3 x100 = 7.64% (w/v) b) molarity - No. Il moles of solute free letne of solution molarity = gaien wohlg) x 1000 molot (og lind) I wol. of soleme) = 3.53 x looo 122.549 45 = 0. 6401 - 640.1 MM. c Molality: et number of moles ber thousand glam of solent m 1000 x Molarity (1000x sp granity) - (molarity - mol. ofsolube Hell sp. gravity - g. of solutur vol. ofsolution = 3.53 = 0.0784. glm. us molefsolute = green not 3.53 of nol wt of solute 122.4g ghnos = 0.02880

malality = 10oo x 0.6401 llooo X 0.07841-(0.491 - 0.02880) 640.1 78.4 - 0,6113 640.1 77.7887 = 8.2287 molal. u mole flaction of salt X = mole of salt moles of salt tmoles of solent moles of salt - given wt of salt molcwn of salt = 3.53/122,549 = 0.02980 moless moles of solvents - whof solent weda Relatenship between molality & mole flacten me molality. m XA - 55.5 tm 8228 55.578.228 8:228 = 0.129 63.728