P (x,y,z)
distance from P1 (2, -1,4)
2 =
(x-2)2 + (y+1)2 + (z-4)2
P2(3,4,-3) : (-12+9
)2
= (x-3)2 + (y-4)2 + (z+3)2
P3(4,-2,6) ; (-1)2 =
(x-4)2 + (y+2)2 + (z-6)2
P4(6,4,12) : (-9)2 =
(x-6)2 + (y-4)2 +
(z-12)2
expanding the terms
2 =
(x2 +y2 + z2) -4x +2y - 8z +
21
2 +
(144 +81*3 -216
) -
(24-18
)
=
(x2 +y2 + z2) -6x -8y + 6z +
34
2 -
2
+1 =
(x2 +y2 + z2) -8x +4y - 12z
2 -
18
+81 =
(x2 +y2 + z2) - 12x - 18y -
24z
re-arrange the terms and put s = 2 -
(x2 +y2 + z2)
-4x +2y - 8z + 0 = s-21
-6x - 8y +6z + (24-18)
= s
+353 - 216
-8x +4y - 12z + 2 = s-55
-12x -8y - 24z + 18 = s-115
We have 4 variables and 4 equations, solving them we get
x= -0.185s +37.22
y = 0.53s +16.39
z= 0.1s +2.07
= 0.3s +7.64
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