5. A mixture of Na2CO3 and NaHCO3 has a mass of 3.80 g and con- tains...
A mixture of Na2CO3 and NaHCO3 has a mass of 22 gram. Treatment with excess HCL solution liberates 6 litre of CO2 at 25 degree Celsius and 0.947 atm pressure. Determine the percent of Na2CO3 in the mixture?
Determine the mass (in g) of each sucrose solution that con- tains 12 g of sucrose. (a) 4.1% sucrose by mass (b) 3.2% sucrose by mass (c) 12.5% sucrose by mass
11. NaHCO, decomposes when exposed to heat: 2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(e) AH = 91.5 kJ What mass of NaHCO3 is decomposed by 256 kJ?!
Data: Mass of crucible and cover (g): 30.1500g Mass of crucible, cover, and mixture (g): 30.6208 Mass of crucible, cover, and residue after reaction with HCl (g): 1st weighing: 30.1371g 2nd weighing: 30.1372g Mass of unknown sample: .4708g Mass of NaCl formed: .01285g A. Solve the two equations and calculate the mass of NaHCO3 and the mass of Na2CO3- NaHCO3+HCl--->NaCl+CO2+H2O NaCO3+2HCl--->2NaCl+CO2+H2O B. Calculate the percent NaHCO3 in the mixture. C. Calculate the average percent by mass of other elements in...
1.Sodium hydrogen carbonate, NaHCO3, can be decomposed completely by heating. 2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) A sample of impure NaHCO3 with an initial mass of 0.739 g yielded a solid residue (consisting of Na2CO3 and other solids) with a final mass of 0.564 g. Determine the mass percent of NaHCO3 in the sample. 2.In a process for producing acetic acid, oxygen gas is bubbled into acetaldehyde, CH3CHO, containing manganese(II) acetate (catalyst) under pressure at 60°C. 2CH3CHO(l) +...
3. Using the mass of NaHCO3, calculate the number of moles of NaHCO3. PART A: REACTION STOICHIOMETRY Thala Tablet 1 Tablet 2 Average Data 20.2g 1,99 a 194.919 187.31 g Mass of NaHCO, Mass of Beaker + Acetic Acid + NaHCO, +Watch Glass before Reaction Mass of Beaker + Reaction Mixture + Watch Glass after Reaction Calculated Results (see below for guidance) Mass of CO2 Gas Released 1:02 g Moles of CO2 Gas Released 0.6231 Ymol 0.02227 mol Moles of...
Possible Chemical Equations NaHCO3 (s) → NaOH (s) CO2(g) NaHCO3 (s) → Na2CO3(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na2O(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na(s) + H2(g) + C(s) + O2(g) Conclusions: 1. Rewrite and balance each of the four chemical equations from the lab introduction.
Possible Chemical Equations NaHCO3 (s) → NaOH (s) CO2(g) NaHCO3 (s) → Na2CO3(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na2O(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na(s) + H2(g) + C(s) + O2(g) Conclusions: 1. Rewrite and balance each of the four chemical equations from the lab introduction.
Which is the correct equilibrium constant expression for the following reaction? 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) O A. Kc=[Na2CO3] / [NaHCO3)2 O B. Kc = [NaHCO3] 2 / [Na2CO3][ CO2][ H20] O C. Kc = [ CO2][ H20] OD. Kc = [Na2CO3][ CO2][ H20] / [NaHCO3)2
B. Percentage of NaHCO3 in an Unknown Mixture UNKNOWN # 134 mass of test tube + unknown mixture (before heating) 33,20 34,027 31.48 mass of test tube 31,538 mass of unknown mixture 32,6912 33.283 mass of test tube + residue (after heating) RECYCLE Chemical Waste mass of H2CO3 (H2O + CO2) 8 (before heating - after heating) Show the calculation for the mass of NaHCO3 in the unknown mixture for trial 1 (see Example Exercise 14.2). mass of NaHCO3 g...