Eo (Pb2+/Pb) = -0.13 V
Eo(Fe2+/Fe) = -0.44 V
Eo (Al3+/Al)= -1.66 V
Eo(F2/F-)= 2.87 V
Eo(Cl2/Cl-)= 1.36 V
Eo(Br2/Br-)=1.09 V
the one with greateest Eo value will be reduced at
cathode
The Eo with the smallest EO value will be oxidised at
anode
At cathode:
F2 is produced
at anode: Al is produced
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