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A potential difference (p.d.) of 4800 V is applied between the cathode and anode of the tube. The cathode is heated and electAfter leaving the anode, the electrons follow a parabolic path as they pass between a pair of parallel plates with a p.d. of

A potential difference (p.d.) of 4800 V is applied between the cathode and anode of the tube. The cathode is heated and electrons are emitted from its surface. These electrons are then accelerated from rest and pass through a hole in the anode Cathode Anode Electrons 4800 V Show that the speed v of the electrons as they leave the anode is about 4 x 107 m s-1. V
After leaving the anode, the electrons follow a parabolic path as they pass between a pair of parallel plates with a p.d. of 800 V between them. There is a uniform electric field between the plates o 800 V Cathode Anode h V 5 cm electron beam 0 V 15 cm 4800 V
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Here, quustion Speed the anode IS to find out the l eave they v of the electrons as kinehc energyganed by the electrons will

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