A 0.2688 g sample of a monoprotic acid neutralized 16.4 mL of a 0.08133 M LioH...
5 points A mass of 0.4231 grams of an unknown monoprotic acid was neutralized with 13.57 ml of a 0.3026 M solution of KOH. Calculate the molar mass of the acid Reports in grams with dem but no units
A 50.0 mL solution of 0.805 M acetic acid, a monoprotic acid, is completely neutralized by the addition of 23.55 mL of sodium hydroxide. What is the concentration of the initial sodium hydroxide solution? What is the final concentration of the sodium ions in mol/L? In the reaction in question 1, the initial temperature of each solution is 22.1°C. The temperature after mixing is 29.4°C. How much heat is liberated by this neutralization reaction? What is the heat of neutralization...
A 0.4352-g sample of an unknown monoprotic acid is dissolved in water and titrated with standardized potassium hydroxide. The equivalence point in the titration is reached after the addition of 31.14 mL of 0.1833 M potassium hydroxide to the sample of the unknown acid. Calculate the molar mass of the acid. _____ g/mol
a) A 25.00-mL sample of monoprotic acid was titrated with 0.0800 M potassium hydroxide solution. The equivalence point was reached after 18.75 mL of base was added. Calculate the concentration of the acid. b) A 15.00-mL sample of 0.120 M nitric acid was titrated with 0.0800 M potassium hydroxide. Calculate the pH of the sample when 10.00 mL of the base has been added.
Enter your answer in the provided box. A 0.2411-g sample of a monoprotic acid neutralizes 24.72 mL of a 0.07625 M KOH solution. Calculate the molar mass of the acid. I g/mol
7. + -19 points My Notes A 2.256-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of solution. 35.0 mL of this solution was titrated with 0.08152-M NaOH. The pH after the addition of 25.80 mL of base was 6.74, and the equivalence point was reached with the addition of 48.31 mL of base. a) How many millimoles of acid are in the original solid sample? Hint: Don't forget the dilution. mmol acid b) What...
A 0.767 g sample of a monoprotic acid is dissolved in water and titrated with 0.190 M KOH. What is the molar mass of the acid if 32.0 mL of the KOH solution is required to neutralize the sample? molar mass: g/mol
A 0.597 g sample of a monoprotic acid is dissolved in water and titrated with 0.160 M KOH. What is the molar mass of the acid if 27.0 mL of the KOH solution is required to neutralize the sample? molar mass: g/mol
A 0.298 g sample of a monoprotic acid is dissolved in water and titrated with 0.320 M KOH. What is the molar mass of the acid if 15.5 mL of the KOH solution is required to neutralize the sample? molar mass: ________ g/mol
A 0.699 g sample of a monoprotic acid is dissolved in water and titrated with 0.240 M NaOH. What is the molar mass of the acid if 30.0 mL of the NaOH solution is required to neutralize the sample? molar mass: g/mol