Balanced chemical equation is:
KOH + HA ---> KA + H2O
lets calculate the mol of KOH
volume , V = 32 mL
= 3.2*10^-2 L
use:
number of mol,
n = Molarity * Volume
= 0.19*3.2*10^-2
= 6.08*10^-3 mol
According to balanced equation
mol of HA reacted = (1/1)* moles of KOH
= (1/1)*6.08*10^-3
= 6.08*10^-3 mol
This is number of moles of HA
mass(HA)= 0.767 g
use:
number of mol = mass / molar mass
6.08*10^-3 mol = (0.767 g)/molar mass
molar mass = 1.262*10^2 g/mol
Answer: 1.26*10^2 g/mol
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