Enter your answer in the provided box. A 0.2411-g sample of a monoprotic acid neutralizes 24.72 mL of a 0.07625 M KOH s...

Question

Question

Enter your answer in the provided box. A 0.2411-g sample of a monoprotic acid neutralizes 24.72 mL of a 0.07625 M KOH solutio

Answer 1

Answer #1

HAT KOH → KAT H₂O Moles of kom nolarilyx volume in L - 0.07625 MX (24.72x1032) - 1.885x 103 moles Holes y HA enacted = 1.8858

Answer 2

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