Homework Answers
capcitance of upper wire
Cu = 3 * 6 / ( 3 + 6) = 2 uF
capcitance of lower wire
CL = 3* 6 / ( 3 + 6) = 2 uF
net capacitance
C = Cu + CL = 4 uF
=======
b)
charge through upper wire
qu = Cu V = 2* 200 = 400 uC
charge through lower wire
qL = CL V = 2 * 200 = 400 uC
now
VCd = |V1 - V4|
Vcd = qu/C1 - qL/c4
Vcd = 400 / 3 - 400/6
Vcd = 66.67 V
======
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