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![16-02-2 뉴 -44p) = 4 (-349 +v]] -22 뉴1-+40) - JR l -gu +v)] + - 440 - - ++ , 40 - s 는 1259 - - 나 +4JC 124 440-242 11 A - - 242](http://img.homeworklib.com/questions/2bb182e0-40af-11eb-a9a8-f7a14b78f750.png?x-oss-process=image/resize,w_560)
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just set up the integral
8) SET-UP an integral to evaluat - 8x)dA, where Ris the...
Use the given transformation to evaluate the given integral, where R is the parallelogram with vertices...
Use the given transformation to evaluate the given integral, where R is the parallelogram with vertices (-2, 6), (2, -6), (5,-3), and (1,9). L = SUR(16.+12y) dA; r = {(u +v), y=(v – 3u) L =
Use the given transformation to evaluate the integral. 1 (20x + 157) da, where is the...
Use the given transformation to evaluate the integral. 1 (20x + 157) da, where is the parallelogram with vertices (-2, 6), (2, -8), (4,-6), and (0, 10); x = (u + v), y - 4)
Use the given transformation to evaluate the integral. + 16y) da, where R is the parallelogram...
Use the given transformation to evaluate the integral. + 16y) da, where R is the parallelogram with vertices (-2, 6), (2,-6), (4,-4), and (0,8); x =
1.1. Find the absolute and minimum values of f(x, y) = xy? on the set D=...
1.1. Find the absolute and minimum values of f(x, y) = xy? on the set D= {(x, y)\x² + y si 1.2. Find the extreme values of f(x,y) = x² + y2 + 4x-4y, using the Lagrange multipliers, with the constraint x² + y² 59 1.3. Evaluate the integral - Le*dxdy 1.4. Evaluate the integral L1.** sin(x+ + gydydx 1.5. Find the area of the surface x + y2 +22 - 4 that lies above the plane z = 1....
1/3 x + y 7. Consider dA where R is the region bounded by the triangle...
1/3 x + y 7. Consider dA where R is the region bounded by the triangle with vertices (0,0), (2,0), V= x+y X-y and (0,-2). The change of variables u=- defines a transformation T(x,y)=(u,v) from the xy-plane 2 to the uv-plane. (a) (10 pts) Write S (in terms of u and v) using set- builder notation, where T:R→S. Use T to help you sketch S in the uv-plane by evaluating T at the vertices. - 1 a(u,v) (b) (4 pts)...
(b) Evaluate the double integral e(y-2)/(y+2) dA where D is the triangle with vertices (0,0), (2,0)...
(b) Evaluate the double integral e(y-2)/(y+2) dA where D is the triangle with vertices (0,0), (2,0) and (0,2). (Hint: Change variables, let u = y - x and v = y + x.)
5. Evaluate SS x+2y da where R is the triangle with vertices (0,3), (4,1), and (2,6)....
5. Evaluate SS x+2y da where R is the triangle with vertices (0,3), (4,1), and (2,6). Use the transformation x=-(u- *=£cu-v),= (3u+v+12). 6. Evaluate S 2 ydx+(1 – x)dy along the curve C given by y=1 –x" from x = -1 to x = 2.
No need to solve the integral just set up with bounds. ) 8. Let C be...
No need to solve the integral just set up
with bounds.
) 8. Let C be the triangle which goes from (0,0) to (0,1) to (2,1) and back to (0,0). Let F(x, y) = < 2x”y–sin x,cos y + x'y4 >. Use Green's Theorem to set up a double integral equal to Ic F.dr.
Calculate the integral using the type II method after the transformation: = SSR xy dA, where...
Calculate the integral using the type II method after the transformation: = SSR xy dA, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/v and y = v
Calculate the integral: I = NSR xy dA, where R is the region in the first...
Calculate the integral: I = NSR xy dA, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/v and y = v Bonus: If you have done a type I integration, can you give an expression for a type II (no calculation) integral and vice-versa, or can you explain why one integral is preferable over the...
Use the given transformation to evaluate the given integral, where R is the parallelogram with vertices (-2, 6), (2, -6), (5,-3), and (1,9). L = SUR(16.+12y) dA; r = {(u +v), y=(v – 3u) L =
Use the given transformation to evaluate the integral. 1 (20x + 157) da, where is the parallelogram with vertices (-2, 6), (2, -8), (4,-6), and (0, 10); x = (u + v), y - 4)
Use the given transformation to evaluate the integral. + 16y) da, where R is the parallelogram with vertices (-2, 6), (2,-6), (4,-4), and (0,8); x =
1.1. Find the absolute and minimum values of f(x, y) = xy? on the set D= {(x, y)\x² + y si 1.2. Find the extreme values of f(x,y) = x² + y2 + 4x-4y, using the Lagrange multipliers, with the constraint x² + y² 59 1.3. Evaluate the integral - Le*dxdy 1.4. Evaluate the integral L1.** sin(x+ + gydydx 1.5. Find the area of the surface x + y2 +22 - 4 that lies above the plane z = 1....
1/3 x + y 7. Consider dA where R is the region bounded by the triangle with vertices (0,0), (2,0), V= x+y X-y and (0,-2). The change of variables u=- defines a transformation T(x,y)=(u,v) from the xy-plane 2 to the uv-plane. (a) (10 pts) Write S (in terms of u and v) using set- builder notation, where T:R→S. Use T to help you sketch S in the uv-plane by evaluating T at the vertices. - 1 a(u,v) (b) (4 pts)...
(b) Evaluate the double integral e(y-2)/(y+2) dA where D is the triangle with vertices (0,0), (2,0) and (0,2). (Hint: Change variables, let u = y - x and v = y + x.)
5. Evaluate SS x+2y da where R is the triangle with vertices (0,3), (4,1), and (2,6). Use the transformation x=-(u- *=£cu-v),= (3u+v+12). 6. Evaluate S 2 ydx+(1 – x)dy along the curve C given by y=1 –x" from x = -1 to x = 2.
No need to solve the integral just set up
with bounds.
) 8. Let C be the triangle which goes from (0,0) to (0,1) to (2,1) and back to (0,0). Let F(x, y) = < 2x”y–sin x,cos y + x'y4 >. Use Green's Theorem to set up a double integral equal to Ic F.dr.
Calculate the integral using the type II method after the transformation: = SSR xy dA, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/v and y = v
Calculate the integral: I = NSR xy dA, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/v and y = v Bonus: If you have done a type I integration, can you give an expression for a type II (no calculation) integral and vice-versa, or can you explain why one integral is preferable over the...
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