Use the given transformation to evaluate the integral. + 16y) da, where R is the parallelogram...
Use the given transformation to evaluate the given integral, where R is the parallelogram with vertices (-2, 6), (2, -6), (5,-3), and (1,9). L = SUR(16.+12y) dA; r = {(u +v), y=(v – 3u) L =
Use the given transformation to evaluate the integral. 1 (20x + 157) da, where is the parallelogram with vertices (-2, 6), (2, -8), (4,-6), and (0, 10); x = (u + v), y - 4)
Use the given transformation to evaluate the integral. -5x dx dy where R is the parallelogram bounded by the linesy-x+1, y-x +4 y#2x+2y»2x + 5 A) -5 B) 10 C)5 D)-10 32) y+ x where R is the trapezoid with vertices at (6,0), ,0).。. 6), (0.9) 45 45 B) ÷ sin l 45 C) sin 2 45 A) sin 2 Use the given transformation to evaluate the integral. -5x dx dy where R is the parallelogram bounded by the linesy-x+1,...
Evaluate the given integral by making an appropriate change of variables dA, where R is the parallelogram enclosed by the lines x-7y-0, x-7y-9, 4x-y 6, and 4x-y= 7 R4x -y Need Help? Read ItWatch ItMaster ItTalk to a Tutor
Use the given transformation to evaluate the integral. 10xy da, where is the region in the first quadrant bounded by the lines y = 1x and y = 3x and the hyperbolas xy - 3 and xy = 3; xu/v, y v
Use the given transformation to evaluate the integral. ∫∫R6xy dA, where R is the region in the first quadrant bounded by the lines y = 1/3x and y = 3x and the hyperbolas xy = 1/3 and xy = 3; x = u/v, y = V
Evaluate the integral by making an appropriate change of variables. Slo 3 cos (5(X+3) dA where R is the trapezoidal region with vertices (8,0), (9, 0), (0, 9), and (0,8) 17 sin(5) 2 x
3. Use the transformation u = xy, v = y to evaluate the integral ∫∫R xy dA, where R is the ay region in the first quadrant bounded by the lines y = x and y = 3x, and the hyperbolas xy = 1, xy = 3
Points Use the given transformation to evaluate the integral SLO (20x + 18), where is the paralelogram with vertices (-), 12), (3, -12), (6, -9), and (0, 13); } + 7). 4050
Find integral integral _ 4x + 3y/2x - 3y dA, where R is the parallelogram enclosed by the lines -4x + 3y = 0, - 4x + 3y = 6, 2x - 3y = 1, 2x - 3y = 4 This can be done directly with a tedious computation, or can be done with a change of variables to transform the parallelogram into a rectangle.