Calculations involving a limiting reactant Now consider a situation in which 23.0 g of P4 is...

Question

Question

Calculations involving a limiting reactant Now consider a situation in which 23.0 g of P4 is...

Calculations involving a limiting reactant

Now consider a situation in which 23.0 g of P4 is added to 50.0 g of Cl2, and a chemical reaction occurs. To identify the limiting reactant, you will need to perform two separate calculations:

Calculate the number of moles of PCl5 that can be produced from 23.0 g of P4 (and excess Cl2).

Calculate the number of moles of PCl5 that can be produced from 50.0 g of Cl2 (and excess P4).

Then, compare the two values. The reactant that produces the smaller amount of product is the limiting reactant.

What mass of PCl5 will be produced from the given masses of both reactants?

Express your answer numerically in grams.

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

Add a comment

Answer 2

Similar Homework Help Questions

P4(s)+10Cl2(g)→4PCl5(g) Now consider a situation in which 29.0 g of P4 is added to 55.0 g...

P4(s)+10Cl2(g)→4PCl5(g) Now consider a situation in which 29.0 g of P4 is added to 55.0 g of Cl2, and a chemical reaction occurs. To identify the limiting reactant, you will need to perform two separate calculations: 1. Calculate the number of moles of PCl5 that can be produced from 29.0 g of P4 (and excess Cl2). 2. Calculate the number of moles of PCl5 that can be produced from 55.0 g of Cl2 (and excess P4). 3. Then, compare the...
3)Use the balanced equation: P4 + 10Cl2 → 4PCl5. When 23.0 g P4 and 16.0 g...

3)Use the balanced equation: P4 + 10Cl2 → 4PCl5. When 23.0 g P4 and 16.0 g Cl2 react, how many grams of PCl5 are produced? Which reactant is limiting and which is in excess?
What mass of PCl5 will be produced from the given masses of both reactants? Calculate the...

What mass of PCl5 will be produced from the given masses of both reactants? Calculate the number of moles of PCl5 that can be produced from 23.0 g of P4 (and excess Cl2). 0.743 mole Calculate the number of moles of PCl5 that can be produced from 53.0 g of Cl2 (and excess P4). 0.299 mole

1. How many moles of PCl5 can be produced from 30.0 g of P4 (and excess...

1. How many moles of PCl5 can be produced from 30.0 g of P4 (and excess Cl2)? 2.How many moles of PCl5 can be produced from 59.0 g of Cl2 (and excess P4)? 3.What mass of PCl5 will be produced from the given masses of both reactants?
P4(s)+10Cl2(g)→4PCl5(g) 0.646 mol of PCl5 can be produced from 20g of P4 , 0.3155 mol of...

P4(s)+10Cl2(g)→4PCl5(g) 0.646 mol of PCl5 can be produced from 20g of P4 , 0.3155 mol of PCl5 can be produced from 56 g of Cl2 What mass of PCl5 will be produced from the given masses of both reactants?
Chemistry help needed! 1. How many grams of hydrogen must you start with to prepare 6.00g...

Chemistry help needed! 1. How many grams of hydrogen must you start with to prepare 6.00g of tungsten?(For WO3, MW = 231.8 amu.) 2. What mass of PCl5 will be produced from the given masses of both reactants? PCl5 that can be produced from 22.0g of P4 (and excess Cl2). PCl5 that can be produced from 53.0g of Cl2 (and excess P4). Thanks!

How many moles of PCl5 can be produced from 26.0 g of P4 (and excess Cl2)...

How many moles of PCl5 can be produced from 26.0 g of P4 (and excess Cl2) P4(s)+10Cl2(g)→4PCl5(g)
Consider a situation in which 211 g of P4 are exposed to 240 g of O2....

Consider a situation in which 211 g of P4 are exposed to 240 g of O2. P4+5O2→2P2O5 Maximum number of moles of P2O5 that can theoretically be made from 211 g of P4 and excess oxygen = 3.4 mol Maximum number of moles of P2O5 that can theoretically be made from 240 g of O2 and excess phosphorus = 3 mol Question: What is the percent yield if the actual yield from this reaction is 341 g ? Express your...
P4+5O2→2P2O5 Consider a situation in which 112 g of P4 are exposed to 112 g of...

P4+5O2→2P2O5 Consider a situation in which 112 g of P4 are exposed to 112 g of O2. Part A What is the maximum amount in moles of P2O5 that can theoretically be made from 112 g of P4 and excess oxygen? Part B What is the maximum amount in moles of P2O5 that can theoretically be made from 112 g of O2 and excess phosphorus?

EXPERIMENT # 14 Assuming Na2CO, is the limiting reactant, how many grams of NaCl can be...

EXPERIMENT # 14 Assuming Na2CO, is the limiting reactant, how many grams of NaCl can be produced from the amount of Na2CO, used in this experiment? Show calculations below: 8 Assuming HCI is the limiting reactant, how many gran of NaCl can be produced from the amount of HCI user this experiment? Show calculations below: 8 Which reactant is limiting? Which reactant is excess? 8 Actual yield of NaCl 8 Theoretical yield of NaCl % Percent yield of NaCl Show...

Calculations involving a limiting reactant Now consider a situation in which 23.0 g of P4 is...

Homework Answers

Add Answer to:
Calculations involving a limiting reactant Now consider a situation in which 23.0 g of P4 is...

Post as a guest

Earn Coins

P4(s)+10Cl2(g)→4PCl5(g) Now consider a situation in which 29.0 g of P4 is added to 55.0 g...

3)Use the balanced equation: P4 + 10Cl2 → 4PCl5. When 23.0 g P4 and 16.0 g...

What mass of PCl5 will be produced from the given masses of both reactants? Calculate the...

1. How many moles of PCl5 can be produced from 30.0 g of P4 (and excess...

P4(s)+10Cl2(g)→4PCl5(g) 0.646 mol of PCl5 can be produced from 20g of P4 , 0.3155 mol of...

Chemistry help needed! 1. How many grams of hydrogen must you start with to prepare 6.00g...

How many moles of PCl5 can be produced from 26.0 g of P4 (and excess Cl2)...

Consider a situation in which 211 g of P4 are exposed to 240 g of O2....

P4+5O2→2P2O5 Consider a situation in which 112 g of P4 are exposed to 112 g of...

EXPERIMENT # 14 Assuming Na2CO, is the limiting reactant, how many grams of NaCl can be...

Calculations involving a limiting reactant Now consider a situation in which 23.0 g of P4 is...

Homework Answers

Add Answer to: Calculations involving a limiting reactant Now consider a situation in which 23.0 g of P4 is...

Post as a guest

Earn Coins

Add Answer to:
Calculations involving a limiting reactant Now consider a situation in which 23.0 g of P4 is...