Question

D Question 3 1 pts In a recent survey, 815 out of 2036 adults said they prefer to get their news online. Construct a 95% conf
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Total Number of adults (1) = 2036 Number of Adults prefer to get their News - Sample proportion f 815 = 0.4603 online = 815 9

Add a comment
Know the answer?
Add Answer to:
D Question 3 1 pts In a recent survey, 815 out of 2036 adults said they...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1. In a survey of 2289 adults in a recent year, 1440 say they have made...

    1. In a survey of 2289 adults in a recent year, 1440 say they have made a New Year's resolution. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. 2. In a survey of 3016 adults, 1481 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results.

  • In a survey of 2283 adults in a recent year, 1366 say they have made a...

    In a survey of 2283 adults in a recent year, 1366 say they have made a New Year's resolution. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion pis (D. (Round to three decimal places as needed.) The 95% confidence interval for the population proportion pis ( I. (Round to three decimal places as needed.) With the given confidence, it...

  • In a survey of 2330 ​adults, 700 say they believe in UFOs. Construct a 95 %...

    In a survey of 2330 ​adults, 700 say they believe in UFOs. Construct a 95 % confidence interval for the population proportion of adults who believe in UFOs. A 95​% confidence interval for the population proportion is ​( nothing​, nothing​). ​(Round to three decimal places as​ needed.) Interpret your results. Choose the correct answer below. A. With 95​% ​probability, the population proportion of adults who do not believe in UFOs is between the endpoints of the given confidence interval. B....

  • In a survey of 3384 adults, 1437 say they have started paying bills online in the...

    In a survey of 3384 adults, 1437 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. L .D. A 99% confidence interval for the population proportion is (L (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O O O A. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying...

  • In a survey of 2280 adults, 709 say they believe in UFOS. Construct a 95% confidence...

    In a survey of 2280 adults, 709 say they believe in UFOS. Construct a 95% confidence interval for the population proportion of adults who believe in UFOS. A 95% confidence interval for the population proportion is ( (Round to three decimal places as needed.) ) Interpret your results. Choose the correct answer below O A. With 95% confidence, it can be said that the population proportion of adults who believe in UFOS is between the endpoints of the given confidence...

  • In a survey of 2834 adults, 1448 say they have started paying bills online in the...

    In a survey of 2834 adults, 1448 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (0) (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O A. With 99% confidence, can be said that the population proportion of adults who say they have started paying bills online the last year...

  • In a survey of 2850 adults, 1443 say they have started paying bills online in the...

    In a survey of 2850 adults, 1443 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (0. (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the...

  • tion In a survey of 2973 adults, 1424 say they have started paying bills online in...

    tion In a survey of 2973 adults, 1424 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion Interpret the results A 99% confidence interval for the population proportion is (Round to three decimal places as needed) Interpret your results. Choose the correct answer below. OA. The endpoints of the given confidence interval show that adults pay bills online 99% of the time. OB. With 99% confidence, it can be...

  • In a survey of 2052 adults in a recent year, 724 made a New Year's resolution...

    In a survey of 2052 adults in a recent year, 724 made a New Year's resolution to eat healthier Construct 90% and confidence intervals for the population proportion Interpret the results and compare the widths of the confidence intervals The 90% confidence interval for the population proportion pis (1 (Round to three decimal places as needed.) ) The 95% confidence interval for the population proportion (Round to three decimal places as needed.) is of the With the given confidence it...

  • In a survey of 2023 adults in a recent year, 710 made a New Year's resolution...

    In a survey of 2023 adults in a recent year, 710 made a New Year's resolution to eat healthier. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion p is ( CD. (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is (0) (Round to three decimal places as needed.) v of adults...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT