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HNO2 + 2Cu^2+ + H2) --> No3- + 2Cu+ + 3H+ In the above redox reaction,...

HNO2 + 2Cu^2+ + H2) --> No3- + 2Cu+ + 3H+

In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.

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THE ELEMENTS WHICH GAINS OXIDATION NUMBER IS CONSIDERED TO BE OXIDIZED WHEREAS THE ONE WHICH DECREMENTS THE OXIDATION NUMBER IS SAID TO BE REDUCED .BASED UPON ABOVE DEFINITION THE SOLUTION TO ABOVE PROBLEM IS AS FOLLOWS

Aecording to the reaction Hng + Quut + H No, +26ttgun oxidation Numbers for species are For cetz - +2 For leng, N= +3 OS = 0

HERE SINCE BOTH H2 AND HNO2 HAVE INCREASE IN THEIR OXIDATION NUMBER HENCE THEY ARE BEING OXIDISED AND THUS THE SPECIES WHICH IS BEING OXIDIZED ACT AS REDUCING AGENT

WHEREAS CU+2 IS CHANGING TO CU+1 HENCE IT IS BEING REDUCED THEREFORE IT ACTS AS A OXIDIZING AGENT

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