Question

9. /1 points C110 18.P.013. B MyNotes Ask Your Teacher Two point charges are fixed on they sa negative point charge 1 28 cat : +0.21 m and a positive point charge 2 0 m. A third point charge origin. The net electrostatic force exerted on the charge by the other two charges has a magnitude of 19 N and points in the y direction. Determine the magnitude of +9 is feed at the Additional Materials Section 18.5

Answer 1

Solution: Given that: The Negative charge Q1 = -28 uc positive point charge a, at at y = 0.21 m Y₂ = 0-32m third point charge . q = 8.9 uc marmitude = 190 q, - - 28 uc = -28x10°c , y, = 0.2m 92 - Y . q=8que 8.9x106c we know that, Coulomb's constant k = 8.99x109 Non c Foro on 'q' due to a is - F = kq q y? (8.99x10°) (89x106) (28 x166) - (0.21) F = 50.800 force on 'a' due to ris Fa= A4% (8.99x109) (8.9x106) 92 (0.32) [, - (800:11 X 1099 924 UX

Here, F is Fa is along along positive Ý direction Negative 'y direction since it is since it is attractive xature Repulsive Nature (we' knew F = 190) given ate know that, Net force (F) - 7- F = F,-F₂ 19N = 50.800 - FC .: F = 50.800 – 19 F2 = 31.500N = 31.800 N (800.41x18)ą, = 31.600 N 31.800 800:11x103 ": 3.1+ x10°C 2 92 = 3.974x105c = 39.74x100c q₂ = 39.24 MC