Question

My Notes Previous Answers CJ10 18.P.012. Ask Your Teacher 5. 0/1 points Two charges attract each other with a force of 1.2 N. What will be the force if the distance between them is reduced to one-third of its original value? x N 0.8 Additional Materials Section 18.5 My Notes 0/1 points Previous Answers CJ10 18.P.013. Ask Your Teacher 6. Two point charges are fixed on the y axis: a negative point charge qi = -26 HC at y10.19 m and a positive point charge q2 at y2 +0.33 m. A third point charge q +8.1 HC is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 19 N and points in the +y direction. Determine the magnitude of q2. x C 50 Additional Materials Section 18.5

Answer 1

5 and let the were at two charges have change a distance "y" initially q, & q2 then :- force = 9.92 - 1-2 N Un to rz reduced to one third of when distance original - force : is r = (1/2) 9.22 UN GO (M) 2Cum hora) ** 2(أ) une Luktor? - (9x1.2) N. forc I 10.8 N Answer q = -26 pc = - 26x106c q = silme = 81x10c since, q, is negitively charged & a is positively Charged: 9, will attract q to itself (in positive y-direction } whill as will repel q (& apply force in negitive y direction].

Hence, force (force by q, an q) e (force by q an q) = met 9,9 = 19. unto Co.1972 Unto (0.33)2 es lo 4. (4.260 + 14 4 360.397 en av ] *67) 9 (+26x10 19 x 10 x 6.3 9 ) 1x8. Q2 = (+7.2x10 + 2.61×10] x (0.33)2 C 122 = 1.07x10 cl Answer -4 1.07 x 10 c Answes