Part a
The balanced reaction
CO(g) + 2H2(g) = CH3OH(l)
Entropy change for the reaction = sum of Entropy of formation of products - sum of Entropy of formation of reactants
ΔS°rxn = Sf(CH3OH) - Sf(CO) - 2*Sf(H2)
= 126.8 - 197.67 - 2*130.68
= - 332.23 J/K
Part b
The balanced reaction
N2(g) + 3H2(g) = 2NH3(g)
Entropy change for the reaction = sum of Entropy of formation of products - sum of Entropy of formation of reactants
ΔS°rxn = 2*Sf(NH3) - Sf(N2) - 3*Sf(H2)
= 2*192.45 - 191.61 - 3*130.68
= - 198.75 J/K
Use the data from this table of thermodynamic properties to calculate the values of ASn for...
Use the data from this table of thermodynamic properties to calculate the values of Δ?∘rxn for each of the reactions at 25∘ C. A. CO(g)+2H2(g)⟶CH3OH(l) B. N2(g)+3H2(g)⟶2NH3(g)
the second part. Use the data from this table of thermodynamic properties to calculate the values of AS for each of the reactions at 25°C. 2 CO(g) + O2(g) 200,(g) ASE= -173.2 N,(€) +0,(€) -> 2NO(0) ASE
Use the data from this table of thermodynamic properties to calculate the values of ASX for each of the reactions at 25°C 2 CO(g) + 0,() — 200,(8) AS = C,H, () +50,(E) + 3 CO, () + 4 H 0(1) ASpan=
need help with the second one Use the data from this table of thermodynamic properties to calculate the values of ASin for each reaction at 25 °C. CO(g) + 2H,(8) CH, OH(1) AS;.. = -332.238 J/mol K 2H,0,0) + 2H2O(l) + 0,() AS = J/mol K
Use the data from this table of thermodynamic properties to calculate the values of ASixn for each reaction at 25 °C. 4NH,(g) + 70,(9) — 4NO2(g) + 6H2O(g) AS:n = J/mol K N,() + 0,(g) 2 NO(g) J/mol K Asian = MISU415) -1065.25 N2(9) N2H4(0) 50.6 N20(9) 81.6 N204(9) 11.1 N205(9) 13.3 NH3(9) -45.9 NH3(aq) -80.29 NH,+(aq) -133.3 NH4CI(S) -314.4 NH4NO3(s) -365.6 (NH2)2CO(s) -333.1 Na(s) Na+(aq) -240.3 Na2CO3(S) -1130.7 NaCl(s) -411.2 NaF(s) -576.6 NaBr(s) -361.1 Nal(s) -287.8 NaNO3(s) -467.9 NaOH(s)...
1. Consider the reaction H2(g) + F2(g) ----->2HF(g) Use the standard thermodynamic data in the tables linked above. Calculate delta G for this reaction at 298.15K if the pressure of HF(g) is reduced to 11.42 mm Hg, while the pressures of H2(g) and F2(g) remain at 1 atm. ANSWER: _____ kJ/mol 2. Consider the reaction N2(g) + 3H2(g) ------>2NH3(g) Using the standard thermodynamic data in the tables linked above, calculate delta Grxn for this reaction at 298.15K if the pressure...
Calculate the equilibrium constant from the standard free energy change. Using standard thermodynamic data (linked), calculate the equilibrium constant at 298.15 K for the following reaction. N2(g) + 3H2(9) 2NH3(g)
estion 13 From the table of thermodynamic data shown here calculate the following thermodynamic properties at 298 K for 2 Alis) + 3 Cl2(g) 2 AICI3(s) 솨f.-1408,4 kJ/mol Consult Textbook Your Answers a) ASsys JK1 mol-1 JKt mott Complete parts al and b first Submit>
Use data from the table below to calculate the equilibrium constants at 25∘C for each reaction. Standard Thermodynamic Quantities for Selected Substances at 25∘C Substance ΔH∘f(kJ/mol) ΔG∘f(kJ/mol) S∘(J/mol⋅K) H2(g) 0 0 130.7 N2(g) 0 0 191.6 O2(g) 0 0 205.2 NO(g) 91.3 87.6 210.8 NO2(g) 33.2 51.3 240.1 CO(g) -110.5 -137.2 197.7 CO2(g) -393.5 -394.4 213.8 H2S(g) -20.6 -33.4 205.8 S2(g) 128.6 79.7 228.2 1. N2(g)+O2(g)⇌2NO(g)
Use data given below to calculate ΔrS∘ΔrS∘ for each of the reactions. Standard Thermodynamic Quantities for Selected Substances at 25 ∘C∘C Substance ΔrS∘ΔrS∘, JK−1mol−1JK−1mol−1 Cr(s)Cr(s) 23.8 Cr2O3Cr2O3(s)(s) 81.2 CO(g)CO(g) 197.7 CO2(g)CO2(g) 213.8 H2(g)H2(g) 130.7 H2O(g)H2O(g) 188.8 H2O(l)H2O(l) 70.0 HNO3(aq)HNO3(aq) 146.0 N2(g)N2(g) 191.6 N2O4(g)N2O4(g) 304.4 NO(g)NO(g) 210.8 NO2(g)NO2(g) 240.1 O2(g)O2(g) 205.2 SO2(g)SO2(g) 248.2 SO3(g)SO3(g) 256.8 A) 4NO2(g)+2H2O(l)+O2(g)→4HNO3(aq) B) Cr2O3Cr2O3(s)(s) +3CO(g)→2Cr(s)+3CO2(g) C) SO2(g)SO2(g) +12O2(g)→SO3(g) D) N2O4(g)+4H2(g)→N2(g)+4H2O(g)