Question

The incidence of a certain type of chromosome defect in the U.S. adult male population is...

The incidence of a certain type of chromosome defect in the U.S. adult male population is believed to be 1 in 75. A random sample of 800 individuals in U.S. penal institutions reveals 16 who have such defects. Level of significance = 5%.

(a) Can it be concluded that the incidence rate of this defect among prisoners differs from the presumed rate for the entire adult male population?

(b) What is the p-value of this test.

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Answer #1

a)

No. there is not enough evidence to claim that the population proportion p1 is different than

p2​, at the 0.05 significance level

b)

p=0.6892

The following null and alternative hypotheses need to be tested: This corresponds to a two-tailed test, for which a z-test for two population proportions needs to be conducted 2) Rejection Region Based on the information provided, the significance level is a = 0.05, and the critical value for a two- tailed test is:c-1.96. The rejection region for this two-tailed test is R 1.96) The z-statistic is computed as follows: 0.0133-0.02 p1 - P2 νp(1-P)(1/n1 1/n2) v0.0194 . (1-0.0194)(1/75-1/800) Since it is observed th0.4 1.96, it is then concluded that the null hypothesis is not rejected Using the P-value approach: The p-value is p 0.6892, and since p 0.6892 2 0.05, it is concluded that the null hypothesis is not rejected. (5) Conclusion It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population proportion Pi is different than p2, at the 0.05 significance level.

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