Question

Part 8 of 8 - Analyze Tamsen and Vera imagine visiting another planet, planet X, whose gravitational acceleration, 9x, is different from that of Earth's. They envision a pendulum, whose period on Earth is 2.243 s, that is set in motion on planet X, and the period is measured to be 1.530 s. What is the ratio of gx/9Earth? Neglect any effects caused by air resistance. 9x ge If the average density of planet X is equal to Earth's average density, Pe, what is the ratio of Ry/Re, where Re is the mean radius of Earth? (Assume both planets are spherical. Recall that p = m/V and Vsphere = r.) Rx RE For the pendulum to have the same period on planet X as on Earth, would the string length need to be longer or shorter? longer shorter Submit Skip (you cannot come back) Need Help? Read it

Answer 1

TE= 2. 2435 Tx = 1.535 we know T = 29.5 7 7 os leneth of pendulum same TE - 9x - 1 TE2 Tx ge TE Tx gx or. FA? 9x - 2015 SE o so sy = 2.15X9.8=21.06m/s2 we know g= GM -GUR38 R2 R? g= UITGPR Эх RY = 2.15 ЭЕ C) As vatre of g is more on y planet so leneth of string need to be longer for same time period