Question

Arrays Program 0 (Warm-up. 40 pts): Deoxyribonucleic acid, or DNA, is comprised of four bases: (G)uanine, (C)ytosine, (A)denine and (T)hymine. Ribonucleic acid, or RNA, is different than DNA in that it contains no Thymine; thymine is replaced with something called (U)racil. For this assignment, you will create an array of 255 characters. You must start by filling the array with random characters of G, C, A and T. You must then print out the array. Next, replace all the instances of Thymine with Uracil. Finally, you must print out the array again. In your solution, you must write at least one function that contributes to the solution. You must use the length attribute of the array in your answer. Sample run CATGGCGTCTTGCCAAGGCGGTTCCTTGTCTTGATGATGGCTGCGAGTTCCGAGTCGCCTTTTCTATGAGTCGCGA AGTATGCGGTCAAATTATGCTTGTCCGCTGTACTAGGCCCACGGATCTCCTCAGACAGCGTCGATGTCGGAATTCG CGGGGAGGAATACTAAACATGCTGAAGTTGATACATGTACAATTGCCGCGAACCAGGTGCACAGGGTGCCCAACGI TCCATGTGGAACGAGAGCGATSTAGCC CAUGGCGUCUUGCCAAGGCGGUUCCUUGUCUUGAUGAUGGCUGCGAGUUCCGAGUCGCCUUUUCUAUGAGUCGCG AGUAUGCGGUCAAAUUAUGCUUGUCCGCUGUACUAGGCCCACGGAUCUCCUCAGACAGCGUCGAUGUCGGAAUU CGGGGAGGAAUACUAAACAUGCUGAAGUUGAUACAUGUACAAUUGCCGCGAACCAGGUGCACAGGGUGCCCAACO "CCAUGUGGAACGAGAGCGAUCUAGCC

Java source code ?

Answer 1

Here is the solution to the above question. The explanation is done in the code itself in the form of comments (see image) for better line by line explanation and better understanding.

Code:

import java.io.*;
public class as15{                                    // main class
   private static int dna_to_rna(char[] dna) {       // function to change DNA into RNA
    int k=dna.length;                               // geting the lendth of pass paramater dna
   char[] rna=new char[k];                       // creating a new array of char type of length same as dna  
   for (int i = 0; i < dna.length; i++) {            // loop to copy dna into rna and change T to U .
           if(dna[i]=='T')
               rna[i]='U';
           else
               rna[i]=dna[i];
        }
   for (int i = 0; i < rna.length; i++) {            // loop to print the rna
            System.out.print(rna[i]);
        }
       return 0;
   }
    public static void main(String args[])            // main function
    {                                                // string having DNA sequence
       String s = "AGTGAGATTCTGCGACTATGTTAACAGGTTGCATCCTGGCGAGTGGGAGGTCAATGTTGTTAGACTGATATGTCTTTATCTTGAGGCCCGGTGCACGGTCGTTGTGTACAATTCAATCTAGGGTCGGACAGCATTCTCGGGTGTCGCGCCTCCTTTACCACGCGACGCCGTACATGTGAGTGCGAGGGTTCAGAGAGTGCCAAGTATTGGCTTTCCCACTAACGATTTCGGATCTCAAGGCTGCCTTCAGACGGG";
        char[] dna = s.toCharArray();                // converting and storing strind into char array
       for (int i = 0; i < dna.length; i++) {        // printing the dna char array
            System.out.print(dna[i]);
        }
       System.out.println("\n");                    // printing new line
       dna_to_rna(dna);                            // calling the function dna_to_rnam to chang and print the rna.
       }
    }

import java. io. Epublic class as15{ /main class private static int dna to_rna(char [] dna) { k-dna. length char rna-new for (int i = 0: i< dna. length; i++) { /function to change DNA into RNA / geting the lendth of pass paramater dna 1 creating a new array of char type of length same as dna 1 loop to copy dna into rna and change T to U . char [k] if (dna [i]T') rna[ilU else rna[i] dna[i]: 10 for (int i = 0: i< rna. length; i++) { 1 loop to print the rna System.out.print(ma[i]); return 0 public static void main(String args[] /main function /string having DMA sequence String s %3D "AGTGAGATTCTGCGACТАТСТТААCAGСTTCCATCСТGGCGAСTGGGAGGTCAАTGTTCTTAGACTGATATGTCTTTАТСТТGAGGCCCGGTCСАCGGTCGTTCTGTACAATTCAAТСТ char [ dna s.toCharArray(); for (int i 0; i < dna.length; i+ { System. out.print(dna[i]) 1 converting and storing strind into char array // printing the dna char array System. out.println("\n"); dna to rna(dna) /printing new line / calling the function dna to_rnam to chang and print the rna.

Output:

AGTGAGATTCTGCGACTATGTTAACAGGTTG CATCCTGGCGAGTGGGAGGTCAATGTTGTTAGACTGATATGTCTTTATCTTGAGGC CCGGTG CACGGTCGTTGTGTACAATTCAAT CTAGGGTCGGACAG CATTCT CGGGTGTCG CG CCTCCTTTACCACG CGACG CCGTACA TGTGAGTG CGAGGGTTCAGAGAGTGCCAAGTATTGG CTTTCCCACTAACGATTT CGGATCT CAAGG CTG CCTTCAGACGGG AGUGAGAUUCUGCGACUAUGUUAACAGGUUGCAUCCUGG CGAG UGGGAGGUCAAUGUUGUUAGACUGAUAUGUCUUUAUCUUGAGGC CCGGUG CACGGUCGUUGUGUACAAUUCAAUCUAGGGUCGGACAG CAUUCUCGGG UG UCG CG CCUCCUUUACCACG CGACG CCGUACA UGUGAGUG CGAGGGUUCAGAGAGUGCCAAGUAUUGG CUUUCCCACUAACGAUUUCGGAUCUCAAGG CUG CCUUCAGACGGG

Note: If you are still unable to understand, then comment with it and I will be happy to help.