How would you put this into MATLAB?
%initializing vector 'n'
n=-20:50;
%creating unit step function u[n]
u_n=zeros(1,length(n));
u_n(n>=0)=1;
%creating unit step function u[n-30]
u_n30=zeros(1,length(n));
u_n30((n-30)>0)=1;
%creating unit step function u[n-20]
u_n20=zeros(1,length(n));
u_n20((n-20)>0)=1;
%creating unit step function u[n+10]
u_n_10=zeros(1,length(n));
u_n_10((n+10)>0)=1;
%creating unit step function u[n+5]
u_n_5=zeros(1,length(n));
u_n_5((n+5)>0)=1;
%obtaining signal x1[n]=u[n]-u[n-30]
x1=u_n-u_n30;
%obtaining signal x2[n]=u[n+10]-u[n-20]
x2=u_n_10-u_n20;
%obtaining signal x3[n]=(1/2)^n(u[n+5]-u[n-20])
x3=(1/2).^n.*(u_n_5-u_n20);
%plotting signal x1(n) vs. n
figure(1)
stem(n,x1)
xlabel('[n]')
ylabel('x_1[n]=u[n]-u[n-30]')
ylim([0 2])
%plotting signal x1(n) vs. n
figure(2)
stem(n,x2)
xlabel('[n]')
ylabel('x_2[n]=u[n+10]-u[n-20]')
ylim([0 2])
%plotting signal x1(n) vs. n
figure(3)
stem(n,x3)
xlabel('[n]')
ylabel('x_3[n]=(1/2)^n(u[n+5]-u[n-20])')
ylim([0 20])
Hi Im a matlab beginner. Would you plz solve my problem? Thanks! Matlab) How to make a code about interpolation?(without using interp1,imresize..etc the internal function) I=[1 10 25 432 28 294 70 80] How to make the I2 whose length is 11 with linear interpolation?(Without matlab function such as imresize!!)
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