Given the following contingency table with category labels A,B,C,X,Y,Z , what Is expected count with 1...
Given the following contingency table with category labels A,B,C,X,Y,Z , what Is expected count with 1 decimal place in the joint category of C and X? Is my calculations right?
Answer 7.0
X. Y. Z.
a. 12. 10. 17
b. 15. 6. 2.
c. 9. 1. 5. Grand total: 77
x total: 36
c total 15
=(15*36)/77
=7.01299
Homework Answers
ANSWER::
x total: ( 12+15+9) = 36
c total: (9 + 1 + 5) =15
Expeted value = Row total * column total / table total
= (9 + 1 + 5) * ( 12+15+9) / (12+15+9+6+10+1+17+2+5)
= 15 * 36 / 77
= 540/77
= 7.0
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