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Given the following contingency table with category labels A,B,C,X,Y,Z , what Is expected count with 1...

Given the following contingency table with category labels A,B,C,X,Y,Z , what Is expected count with 1 decimal place in the joint category of C and X? Is my calculations right?

Answer 7.0

X. Y. Z.

a. 12. 10. 17

b. 15. 6. 2.

c. 9. 1. 5. Grand total: 77
x total: 36

c total 15
=(15*36)/77

=7.01299

math   Statistics-And-Probability   
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Answer #1

ANSWER::

x total: ( 12+15+9) = 36

c total: (9 + 1 + 5) =15

Expeted value = Row total * column total / table total

= (9 + 1 + 5) * ( 12+15+9) / (12+15+9+6+10+1+17+2+5)

= 15 * 36 / 77

= 540/77

= 7.0

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