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Water is supplied at a rate of 100 ft? 5-1, pressure of 50 psi to a turbine through a 5 ft 2 cross-sectional area pipe. The e

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Solution Data giveny Flow Rate (Q) = loott/ Pressure (P) = 50psi = 7200 16/6 Area (All= 5H² A₂ = 2ft² Pe=0 P = 50oh e a coche- WT I = e, -le-hg = 120.9-39.06-10=71-83 ft mg - WT = 1890) 71.83 = 62.88 100x71.83 x= 451139.5 lb.ft I botter - Śso hp - (W→ , = 23.79 + 39.06710 0; = 92.85 ft +V? 38 387 – +2 92.85 = l + 20 to 62.8 - P = 5438.48 Lb/ft? (P = 37.76 esi

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