Question

There are three sets of sketches below, showing the same pure molecular compound (sulfur dioxide, molecular formula SO,) at three different temperatures. The sketches are drawn as if a sample of sulfur dioxide were under a microscope so powerful that individual atoms could be seen. Only one sketch in each set is correct. Use the slider to choose the correct sketch in each set. You may need the following information: En melting point of SO2: -72.0°C boiling point of SO,: -10.0°C (Drag the slider to choose an image) (Drag the slider to choose an image) (Drag the slider to choose an image) 65. °C -43.°C - 106. °C

Answer 1

Here we have pure Sulfur dioxide and its melting point is given as -72 oC and boiling point is given as -10 oC this means:

Any temperature below -72 ^oC SO₂ will be in solid state.

Any temperature above -10 ^oC SO₂ will be in gaseous state.

Any temperature in between the melting temperature and boiling temperature i.e. between -72 ^oC to -10 ^oC, SO₂ will be in liquid state.

In sketch one the given temperature is 65 ^oC this is well above the boiling temperature of SO₂ so it will be in gaseous state so move the slider to show the gas state.

In sketch two the given temperature is -43 ^oC at this temperature SO₂ will be a liquid so move the slider to show the liquid state.

In sketch three the given temperature is -106 ^oC at this temperature SO₂ will be in solid state so move the slider to show the solid state.