as we know that moment generating function Mx(t) =P(x)etx
comparing given mgf to above:
\below is pmf of X:
P(X=1)=2/5
P(X=2)=1/5
P(X=3)=2/5
mean E(X) =xP(x)=1*(2/5)+2*(1/5)+3*(2/5)=10/5=2
E(X2)=x2P(x)=12*(2/5)+22*(1/5)+32*(2/5)=24/5=4.8
hence Variance =E(X2)-(E(X))2 =4.8-22 =0.8
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