Question

What is the approximate isoelectric point of the peptide: Methionine-Histidine-Threonine-Aspartate pKa’s: Methionine: 2.3, 9.2 Histidine: 1.8,...

What is the approximate isoelectric point of the peptide:

Methionine-Histidine-Threonine-Aspartate

pKa’s:


Methionine: 2.3, 9.2
Histidine: 1.8, 9.3, 6.0 (R-group)
Threonine: 2.1, 9.6
Aspartate: 1.9, 9.6, 3.7 (R-group)

Group of answer choices

9.4

2.8

7.6

4.8

1.6

0 0
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Answer #1

Isoelectric pH means pH at which the peptide will have no net charge .

It will be pH 4.8 because at this pH pka of acidic group less than 4.8 will be negative by releasing H+ and pka more than it will be positive by accepting H+.

And here N terminal amino acid methionine has pka 2.3 and aspartate c terminal pka is 9.6.so pH will be in between them so that one POSITIVE and one negative charge and thus net charge becomes zero.

Here is two side chain one is amino present in histidine and one in acidic in aspartate.

So pH should also be in between them to make one acidic negative charge and one amino group positive charge .

So the pH should be in between 3 u and 6 which is 4.8.

Thank you

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