Use Hess's law to calculate AGºrxn using the following information CO(g) → C(s) + 1/2 02(8)...
Q4: Use Hess's law to calculate AGºrxn using the following information. CO(g) + C(s) + 1/2O2(g) AGºrxn = ? CO2(8) C(s) + O2(g) AGºrxn = +394.4 kJ CO(g) + 1/2O2(g) + CO2(g) AGºrxn=-257.2 kJ 1-60.0 Kj B) +137.2 kJ C)-265.8 kJ D ) +651.6 kJ E) +523.0 kJ
Calculate the for the following reaction using Hess's Law: Fez 03 (s) + 3 CO (g) → 2 Fe (s) + 3 CO2 (g) For each blank place, what action must be taken in order to achieve the answer. (For instance, if you need to reverse the reaction, place reverse or (-). If you need to multiply it by a value, place multiply by (number) or X(number).) In Blank #1, place state "I understand." 2 Fe (s) + .2 kJ...
Please show work 63 Use Hess's law to calculate ΔGTXn using the following information . NO(g) + 0(g) → NO2(g) 2。3(g) → 3。2(g) 02(g) → 2 0(g) NO(g) + O3(g) → NO2(g) + O2(g) AGorxn = ? Gorxn +489.6 kJ Grxn = +463.4 kJ ΔGTXn--I 99.5 kJ A) +753.5 kJ B) +277.0 kJ C)-676.0 kJ D) -1152.5 kJ E) -225.7 kJ 64) Calculate ΔGrn at 298 K under the conditions shown below for the foll G"--180.8 kJ 2 Hig(g) +...
Use the following information and hess's law to find the enthalpy change for the reaction C(g) + O2(g) => CO2(g) reaction 1: 2CO(g) + O2(g) => 2CO2(g) ΔH = -566 kj reaction 2: 2C(g) + O2(g) => 2CO(g) ΔH = -1655 kj
Use Hess's law to determine Ofor the reaction → CO2(g),given that C(graphite) +202(8) — CO(8) A Hº = -110.54 kJ mol C(graphite) + O2(8) —CO2(g) A Hº = -393.51 kJ mol
Using Hess's Law, determine the enthalpy change of the following reaction. CS2(1) + 3 O2(g) --> CO2(g) + 2 SO2(g) C(s) + O2(g) --> CO2(g) AH = -393.5 kJ/mol S(s) + O2(g) --> SO2(g) AH = -296.8 kJ/mol C(s) + 25(s) --> CS2(8) AH = +87.9 kJ/mol -899.2 kJ O-778.2 kJ -602.4 kJ - 1075.0 kJ
23. (6 points) Use Hess's law to calculate ΔG.xn using the following information. 2 03(g) -3 02(g) 02(g)-2 0(g) NO(g) + O3(g)--NO2(g) + O2(g) (6 points) Calculate ΔGrxn at 25 °C when P(NO) 0.015 atm, P(O)-0.76 atm, and P(NO2) atm. Is the reaction more or less spontaneous under these conditions? 0.42 -
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol